我正在观察STL类的boost::program_options::value
函数的奇怪行为。
我经常需要为成对的程序提供参数,例如:带有短标签的文件名,但boost::program_options::value
函数似乎不适用于std::pair
,而它适用于我自己定义的任何类。请考虑以下代码:
#include <string>
#include <utility>
#include <boost/program_options.hpp>
using namespace std;
namespace po = boost::program_options;
class sspair: public pair<string,string> { };
typedef pair<string,string> mypair;
// typedef sspair mypair;
istream& operator>>(istream& in, mypair& ss) {
string s;
in >> s;
const size_t sep = s.find(':');
if (sep==string::npos) {
ss.first = string();
ss.second = s;
} else {
ss.first = s.substr(0,sep);
ss.second = s.substr(sep+1);
}
return in;
}
int main(int argc, char **argv)
{
mypair a;
try {
po::options_description all_opt("Options");
all_opt.add_options()
("arg,a", po::value<mypair>(&a),"colon separated pair")
;
po::variables_map vm;
po::store(po::parse_command_line(argc, argv, all_opt), vm);
po::notify(vm);
} catch(exception& e) {
cerr << e.what() << endl;
exit(1);
}
cout << "a = (" << a.first << ", " << a.second << ")" << endl;
return 0;
}
使用typedef sspair mypair
我得到预期的行为。
$ ./test
a = (, )
$ ./test -a b:c
a = (b, c)
$ ./test -a bc
a = (, bc)
但是typedef pair<string,string> mypair
我收到以下编译错误:
In file included from /usr/include/boost/any.hpp:27:0,
from /usr/include/boost/program_options/value_semantic.hpp:12,
from /usr/include/boost/program_options/options_description.hpp:13,
from /usr/include/boost/program_options.hpp:15,
from test.cc:4:
/usr/include/boost/lexical_cast.hpp: In instantiation of ‘struct boost::detail::deduce_target_char_impl<boost::detail::deduce_character_type_later<std::pair<std::basic_string<char>, std::basic_string<char> > > >’:
/usr/include/boost/lexical_cast.hpp:415:89: required from ‘struct boost::detail::deduce_target_char<std::pair<std::basic_string<char>, std::basic_string<char> > >’
/usr/include/boost/lexical_cast.hpp:674:92: required from ‘struct boost::detail::lexical_cast_stream_traits<std::basic_string<char>, std::pair<std::basic_string<char>, std::basic_string<char> > >’
/usr/include/boost/lexical_cast.hpp:2363:19: required from ‘static Target boost::detail::lexical_cast_do_cast<Target, Source>::lexical_cast_impl(const Source&) [with Target = std::pair<std::basic_string<char>, std::basic_string<char> >; Source = std::basic_string<char>]’
/usr/include/boost/lexical_cast.hpp:2543:50: required from ‘Target boost::lexical_cast(const Source&) [with Target = std::pair<std::basic_string<char>, std::basic_string<char> >; Source = std::basic_string<char>]’
/usr/include/boost/program_options/detail/value_semantic.hpp:89:38: required from ‘void boost::program_options::validate(boost::any&, const std::vector<std::basic_string<charT> >&, T*, long int) [with T = std::pair<std::basic_string<char>, std::basic_string<char> >; charT = char]’
/usr/include/boost/program_options/detail/value_semantic.hpp:170:55: required from ‘void boost::program_options::typed_value<T, charT>::xparse(boost::any&, const std::vector<std::basic_string<charT> >&) const [with T = std::pair<std::basic_string<char>, std::basic_string<char> >; charT = char]’
test.cc:49:1: required from here
/usr/include/boost/lexical_cast.hpp:388:13: error: invalid application of ‘sizeof’ to incomplete type ‘boost::STATIC_ASSERTION_FAILURE<false>’
BOOST_STATIC_ASSERT_MSG((result_t::value || boost::has_right_shift<std::basic_istream<wchar_t>, T >::value),
^
make: *** [test] Error 1
我发现如果我尝试使用其他stl容器,例如std::array
或std::tuple
,就会发生类似的行为。
有人知道问题是什么吗?
编辑:
好的,在我阅读post之后,我刚刚发现导致此问题的原因。显然,只在名称空间中查找流运算符,在该名称空间中定义了类(po :: value函数的模板参数)。所以,通过编辑
namespace std {
istream& operator>>(istream& in, mypair& ss) { ... }
}
pair<string,string>
课程可以直接使用。
现在,在std命名空间中定义运算符有什么缺点吗?我听说这本身并不符合标准。
答案 0 :(得分:1)
抱歉,只有时间快速回答。
如果您想使用std::pair<std::string, std:string>
作为配对,则需要为其编写operator>>(...)
,此运算符也需要位于namespace std
中,以便{{1}} 3}}工作。