Question

我试图在一个表格中获取两个单独的数据列。

我有一个跟踪问题的数据库，一个表Issue，有两个相关的列，每个列都包含一个日期。与以下内容非常相似。

DateOpened  DateClosed
2015-01-08  2015-01-08
2015-01-08  2015-01-08
2015-01-06  2015-01-08
2015-01-06  2015-01-08
2015-01-04  2015-01-07
2015-01-02  2015-01-07
2015-01-02  2015-01-07

我的目标是能够计算每个日期打开和关闭的条目数。上面预期输出的一个例子是。

Date          CountDateOpened CountDateClosed
2015-01-08    2               4
2015-01-07    0               3 
2015-01-06    2               0
2015-01-05    0               0
2015-01-04    1               0
2015-01-03    0               0
2015-01-02    2               0

我知道我需要按日期分组，但是应该有几天关闭比打开更多的问题，但我的COUNT（DateClosed）似乎永远不会超过我的Count（DateOpened）。我正在查询中的飞行日期转换，但我不相信它们是相关的，因为我总是到最近的一天。这是我到目前为止运行的查询，为了简单起见，它已被剥离。

SELECT
    CREATEDATE AS [Date],
    COUNT(CREATEDATE) AS [Number Opened],
    COUNT(CLOSEDATE) AS [Number Closed]

FROM
     ISSUE

GROUP BY
     CREATEDATE

ORDER BY 
     [Date] DESC

Answer 1

这样做的一种方法是使用union all为两个日期创建一个列，然后根据其类型进行分组：

SELECT   `Date`, 
         COUNT(`open`) AS `CountDateOpened`
         COUNT(`closed`) AS `CountDateClosed`
FROM     (SELECT `DateOpened` AS `Date`, 1 AS `open`, NULL AS `closed`
          FROM   `issue`
          UNION ALL
          SELECT `DateClosed` AS `Date`, NULL AS `open`, 1 AS `closed`
          FROM   `issue`
         ) t
GROUP BY `Date`
ORDER BY `Date` DESC

Answer 2

试试这个

select 
 d.dt,(select COUNT(DateOpened) ct from ISSUE where
CAST(DateOpened as DATE)=CAST(d.dt as DATE) )
,(select COUNT(DateClosed) ct from ISSUE where
CAST(DateClosed as DATE)=CAST(d.dt as DATE) )
from (
select number,DATEADD(D,number-7,GETDATE()) dt
 from master.dbo.spt_values sp
where type='P' and DATEADD(D,number-7,GETDATE())<'2015-01-09'
)
d
ORDER BY d.dt desc

<强>输出

Date      DateOpened DateClosed
2015-01-08  2            4
2015-01-07  0            3
2015-01-06  2            0
2015-01-05  0            0
2015-01-04  1            0
2015-01-03  0            0
2015-01-02  2            0

Answer 3

与Mureinik的答案相同，只是少打字......

SELECT date,SUM(status='opened') opened, SUM(status = 'closed') closed 
  FROM 
     ( SELECT dateopened date,'opened' status FROM my_table
       UNION ALL
       SELECT dateclosed,'closed' FROM my_table
     ) x
 GROUP  
    BY date DESC;

按相同分组计算2列

3 个答案: