Question

我关注了许多链接，并在表格视图中找到了一个显示复选框的解决方案。但是我无法在表格视图中更改复选框的值。

链接我跟随： How to add CheckBox's to a TableView in JavaFX

模特课程：

public class TUser {
    private SimpleStringProperty name;
    private SimpleStringProperty address;
    private SimpleBooleanProperty active;

public TUser(String name, String address, boolean active) {
    this.name = new SimpleStringProperty(name);
    this.address = new SimpleStringProperty(address);
    this.active = new SimpleBooleanProperty(active);
}

public String getName() {
    return name.get();
}

public void setName(String name) {
    this.name = new SimpleStringProperty(name);
}

public String getAddress() {
    return address.get();
}

public void setAddress(String address) {
    this.address = new SimpleStringProperty(address);
}

public boolean getActive() {
    return active.get();
}

public void setActive(boolean active) {
    this.active = new SimpleBooleanProperty(active);
}

}

FXML文件：

<TableView fx:id="usertable" maxHeight="-Infinity" maxWidth="-Infinity" minHeight="-Infinity" minWidth="-Infinity" prefHeight="400.0" prefWidth="500.0" xmlns="http://javafx.com/javafx/8" xmlns:fx="http://javafx.com/fxml/1">
  <columns>
      <TableColumn fx:id="name" prefWidth="142.0" text="Name" />
    <TableColumn fx:id="address" prefWidth="147.0" text="Address" />
      <TableColumn fx:id="active" prefWidth="153.0" text="Active" />
  </columns>
   <columnResizePolicy>
      <TableView fx:constant="CONSTRAINED_RESIZE_POLICY" />
   </columnResizePolicy>
</TableView>

控制器类：

public class UserManagement extends AnchorPane {

    @FXML
    private TableView<TUser> usertable;
    @FXML
    private TableColumn<TUser, String> address;
    @FXML
    private TableColumn<TUser, String> name;
    @FXML
    private TableColumn<TUser, Boolean> active;

    public UserManagement() throws IOException {
        initGraphics();
        initTable();
    }

    private class CheckBoxCellFactory<S, T> implements Callback<TableColumn<S, T>, TableCell<S, T>> {
    @Override public TableCell<S, T> call(TableColumn<S, T> p) {
        return new CheckBoxTableCell<>();
    }
}

    private void initGraphics() throws IOException {
        FXMLLoader content = new FXMLLoader(getClass().getResource("/mypack/fxmls/UserManagement.fxml"));
        content.setController(this);
        Node contentnode = (Node) content.load();
        AnchorPane.setBottomAnchor(contentnode, 0.0);
        AnchorPane.setLeftAnchor(contentnode, 0.0);
        AnchorPane.setRightAnchor(contentnode, 0.0);
        AnchorPane.setTopAnchor(contentnode, 0.0);
        getChildren().add(contentnode);

        active.setCellFactory(new CheckBoxCellFactory<TUser, Boolean>());

        address.setCellValueFactory(new PropertyValueFactory<TUser, String>("address"));
        name.setCellValueFactory(new PropertyValueFactory<TUser, String>("name"));
        active.setCellValueFactory(new PropertyValueFactory<TUser, Boolean>("active"));

    }

    private void initTable(){
        ObservableList<TUser> data = FXCollections.observableArrayList(new TUser("ABC", "ABC Road", true));
        usertable.setItems(data);
    }

}

输出：

TableView

Answer 1

要使复选框正确绑定到模型类中的属性，您需要定义属性访问器方法：

public class TUser {

    // other methods and fields as before....

    public BooleanProperty activeProperty() {
        return active ;
    }

}

为您的其他属性定义类似的方法也许是一个好主意。

请注意，您的表格不可编辑，因此用户无法操纵复选框。如果您希望它们可以编辑，请将TableView设为可编辑：

<TableView fx:id="usertable" editable="true" ...>

默认情况下，TableColumn可编辑。

JavaFX TableView中的属性绑定不起作用

1 个答案: