阅读row_number

时间:2015-01-08 10:21:35

标签: mysql row-number

输出:https://www.dropbox.com/s/q9bjrzndbzj0l2i/test3.PNG?dl=0

如果我想只获取Position(row_number)= 3,如果让我们说Stud_ID = 4,那么如何将查询合并到当前代码中?

SET @row_num = 0; 
SELECT @row_num := @row_num + 1 as Position, s.* 
FROM
(
    SELECT
        Student.Stud_ID, Student.Stud_Name, Student.Stud_Class, SUM(Grade.Percentage) AS Points 
    FROM Student, Student_Subject, Grade 
    WHERE Student.Stud_ID = Student_Subject.Stud_ID 
        AND Student_Subject.Stud_Subj_ID = Grade.Stud_Subj_ID 
        AND Student.Stud_Form = '1' 
        AND Grade.Quarter = '1' 
    GROUP BY Student.Stud_ID 
    ORDER BY Points DESC
) AS s;

谢谢!

1 个答案:

答案 0 :(得分:1)

对查询使用子选择,并使用所需的行号

对其进行过滤
SELECT * 
FROM (
SELECT @row_num := @row_num + 1 AS `Position`, s.* 
FROM
(
    SELECT
        Student.Stud_ID, Student.Stud_Name, Student.Stud_Class, SUM(Grade.Percentage) AS Points 
    FROM Student, Student_Subject, Grade 
    WHERE Student.Stud_ID = Student_Subject.Stud_ID 
        AND Student_Subject.Stud_Subj_ID = Grade.Stud_Subj_ID 
        AND Student.Stud_Form = '1' 
        AND Grade.Quarter = '1' 
    GROUP BY Student.Stud_ID 
    ORDER BY Points DESC
) AS s
CROSS JOIN (SELECT @row_num := 0) AS s1
) AS t 
WHERE t.Position = 3