如何根据一对多的关系选择人

Question

我有桌子人

create table Person  (
  id SERIAL not null,
  ...
);

person可以有0个或更多PreviousName

create table PreviousName  (
  id       SERIAL    not null,
  person_id INTEGER  not null,
  value     VARCHAR(120)   
);

如何选择以前姓名“John”

中具有例如价值的所有人

Answer 1

select * from Person
where id in (select person_id from PREDCHOZI_JM_PR 
             where value = 'John')

Answer 2

这就是我理解你的问题......

  SELECT * FROM Person LEFT JOIN PREDCHOZI_JM_PR ON person.id=PREDCHOZI_JM_PR.person_id 
  WHERE value="John"

Answer 3

您可以在PREDCHOZI_JM_PR中找到包含john值的不同person_id：

SELECT * FROM Person WHERE id IN (SELECT DISTINCT person_id FROM PREDCHOZI_JM_PR WHERE value LIKE '%John%')