Question

我想找出字符串中特定字符的总出现次数我的代码是：

  $str = 'aabbbcccccaa';

  for ($i=0;$i<strlen($str);$i++){
    $len = 0;
    for ($j=$i;$j<=strlen($str);$j++){
        if($str[$i] == $str[$j]){
        $len++;
        }
    }
    echo "\n".$str[$i].' len is '.$len;
}

我的输出如下：

  a len is 4
  a len is 3
  b len is 3
  b len is 2
  b len is 1
  c len is 5
  c len is 4
  c len is 3
  c len is 2
  c len is 1
  a len is 2
  a len is 1

但我想要像：

  a len is 4
  b len is 3
  c len is 5 only

我怎样才能做到这一点？

Answer 1

<强> RTM

<?php
$data = "Two Ts and one F.";

foreach (count_chars($data, 1) as $i => $val) {
   echo "There were $val instance(s) of \"" , chr($i) , "\" in the string.\n";
}
?>

Answer 2

您应该使用substr_count()。它就在手册中：

http://php.net/manual/en/function.substr-count.php

或者count_chars()对于通用解决方案会更好：

http://php.net/manual/en/function.count-chars.php

在创建自己的东西之前，请务必查看手册..那里可能有一个功能完全符合您的要求..

Answer 3

$str = 'aabbbcccccaa';

foreach (count_chars($str, 1) as $i => $val) {
   echo  chr($i), " len is $val " , "<br>";
}

Answer 4

您好简单实施以下方式！

我们的自定义功能：

function count_chars_unicode($str, $x = false) {
    $tmp = preg_split('//u', $str, -1, PREG_SPLIT_NO_EMPTY);
    foreach ($tmp as $c) {
        $chr[$c] = isset($chr[$c]) ? $chr[$c] + 1 : 1;
    }
    return is_bool($x)
        ? ($x ? $chr : count($chr))
        : $chr[$x];
}

用法：

print_r(count_chars_unicode('aabbbcccccaa', true));

O / P

数组（[a] =＆gt; 4 [b] =＆gt; 3 [c] =＆gt; 5）

print_r(count_chars_unicode('aabbbcccccaa', 'a'));  // frequency of "a"

O / P：4

print_r(count_chars_unicode('aabbbcccccaa'));  // count of uniq chars

O / P：3

如何检查字符串中字符的总出现次数

4 个答案: