我有以下2个数据表
declare @tab1 table(a int, name varchar(10), street varchar(20))
insert @tab1 values(1,'Bruce', 'my street')
insert @tab1 values(2,'Chuck', 'another street')
declare @tab2 table(a int, b varchar(10))
insert @tab2 values(1,'a')
insert @tab2 values(1,'b')
insert @tab2 values(2,'c')
insert @tab2 values(2,'e')
我正在尝试创建一个看起来像这样的XML文档
<Person>
<PersonInfo>
<Name>Bruce</Name>
<Street>my street</Street>
</PersonInfo>
<PersonSkill>
<Type>a</Type>
<Type>b</Type>
</PersonSkill>
</Person>
到目前为止,我的SQL看起来像这样
SELECT name AS "PersonInfo/Name",
street AS "PersonInfo/Street",
b AS "PersonSkill/Type"
FROM @tab1 t1 JOIN @tab2 t2 ON t1.a = t2.a
WHERE NAME = 'Bruce'
FOR XML PATH('Person')
并给出了这个结果
<Person>
<PersonInfo>
<Name>Bruce</Name>
<Street>my street</Street>
</PersonInfo>
<PersonSkill>
<Type>a</Type>
</PersonSkill>
</Person>
<Person>
<PersonInfo>
<Name>Bruce</Name>
<Street>my street</Street>
</PersonInfo>
<PersonSkill>
<Type>b</Type>
</PersonSkill>
</Person>
如何避免收到2份文件?
答案 0 :(得分:2)
在列表列表中针对@tab2
执行相关子查询。
select T1.name as 'PersonInfo/Name',
T1.street as 'PersonInfo/Street',
(
select T2.b as '*'
from @tab2 as T2
where T2.a = T1.a
for xml path('Type'), root('PersonSkill'), type
)
from @tab1 as T1
where T1.name = 'Bruce'
for xml path('Person')