构建Lua中的键/值表

时间:2015-01-08 02:29:56

标签: lua lua-table mud

我正在尝试为我玩的MUD构建一个脚本,它将创建一个表来跟踪每个mob的平均xp。我在检查表中的元素是否存在以及是否创建它时的语法方面遇到了问题。我试过这样的事情但继续得到:attempt to index field '?' (a nil value)

mobz_buried = {
{mob = "troll", quantity = 2}
{mob = "warrior", quantity = 1}
{mob = "wizard", quantity = 1}} -- sample data

number_of_mobz_buried = 4 

xp_from_bury = 2000 -- another script generates these values, these are all just examples

xp_per_corpse = xp_from_bury / number_of_mobz_buried

for _, v in ipairs(mobz_buried) do
    if type(mobz[v].kc) == "variable" then -- kc for 'kill count', number of times killed 
            mobz[v].kc = mobz[v].kc + 1 -- if it exists increment kc
    else
        mobz[v].kc = 1 -- if it doesn't exist create a key value that matches the mobs name and make the kc 1
    end
    if type(mobz[v].xp) == "variable" then -- xp for average experience points
        mobz[v].xp = (((mobz[v].kc - 1) * mobz[v].xp + xp_per_corpse)/mobz[v].kc) -- just my formula to find the average xp over a range of differant buries
    else
            mobz[v].xp = xp_per_corpse -- if it doesn't exist create the table just like before
    end
end

我正在尝试使用mobz.troll = {kc, xp}, mobz.warrior = {kc, xp}, mobz.wizard = {kc, xp},并且能够根据名称mobz_buried添加更多关键值。

1 个答案:

答案 0 :(得分:0)

根据您评论中的额外信息,听起来您没有为mobz构建表格。试试这个:

local mobz = {}
for _, v in ipairs(mobz_buried) do
    mobz[v.mob] = mobz[v.mob] or {}
    mobz[v.mob].kc = (mobz[v.mob].kc or 0) + 1

    -- etc...
end