Question

我有这样的SQL查询：

Select Userid, sum(cast(distanceinKM as int)) as KM, day from( 
SELECT [User].Userid
,[User].ulatitude, [User].ulongitude, [Checkpoint].clatitude, [Checkpoint].clongitutde,
(geography::Point([User].ulatitude, [User].ulongitude, 4326)).STDistance
(geography::Point([Checkpoint].clatitude, [Checkpoint].clongitutde, 4326))/100 as distanceinKM, cast(Timestamp as date) as day

FROM [User] INNER JOIN
Tablelog ON [User].Userid = Tablelog.Userid INNER JOIN
[Checkpoint] ON Tablelog.checkpointid = [Checkpoint].checkpiontid ) as distance 
where Day(day) = 6 AND MONTH (day) = 9 AND YEAR (day) = 2011 
group by userid , day

该功能运行良好，但我的坐标有问题。在我的数据库中，我的坐标以这种方式存储：(55.56490549999999, 9.756640400000038)但在查询中我将它们划分为ulatitude和ulongtitude。所以我手动划分他们，但我不能再这样做，因为我有很多数据。我可以在查询中添加什么内容，因此我采用此格式(55.56490549999999, 9.756640400000038)的坐标并将它们分开。

Answer 1

更新v-4

我已更新查询以符合确切的数据格式。请尝试：

Select 
    distance.Userid, 
    sum(cast(distance.distanceinKM as int)) as KM, 
    distance.[day] 
from
    ( 
        SELECT
            UC_Lat_Long.Userid,
            UC_Lat_Long.ulatitude,
            UC_Lat_Long.ulongitude,
            UC_Lat_Long.clatitude,
            UC_Lat_Long.clongitutde, 
            (geography::Point(UC_Lat_Long.ulatitude, UC_Lat_Long.ulongitude, 4326)).STDistance(geography::Point(UC_Lat_Long.clatitude, UC_Lat_Long.clongitutde, 4326))/100 as distanceinKM, 
            UC_Lat_Long.[day] 
        FROM
        (
            SELECT 
                [User].Userid,
                CONVERT(NUMERIC(28,8), LTRIM(RTRIM(SUBSTRING(ISNULL([User].Coordinates, '0,0'), 1, CHARINDEX(',', ISNULL([User].Coordinates, '0,0')) - 1)))) AS ulatitude, 
                CONVERT(NUMERIC(28,8), LTRIM(RTRIM(SUBSTRING(ISNULL([User].Coordinates, '0,0'), CHARINDEX(',', ISNULL([User].Coordinates, '0,0')) + 1, LEN(ISNULL([User].Coordinates, '0,0')) - CHARINDEX(',', ISNULL([User].Coordinates, '0,0')) - 1)))) AS ulongitude, 
                CONVERT(NUMERIC(28,8), LTRIM(RTRIM(SUBSTRING(ISNULL([Checkpoint].coordinates, '0,0'), 1, CHARINDEX(',', ISNULL([Checkpoint].coordinates, '0,0')) - 1)))) AS clatitude, 
                CONVERT(NUMERIC(28,8), LTRIM(RTRIM(SUBSTRING(ISNULL([Checkpoint].coordinates, '0,0'), CHARINDEX(',', ISNULL([Checkpoint].coordinates, '0,0')) + 1, LEN(ISNULL([Checkpoint].coordinates, '0,0')) - CHARINDEX(',', ISNULL([Checkpoint].coordinates, '0,0')) - 1)))) AS clongitutde, 
                cast([Timestamp] as date) as [day]
            FROM 
                [User] 
                INNER JOIN Tablelog ON [User].Userid = Tablelog.Userid 
                INNER JOIN [Checkpoint] ON Tablelog.checkpointid = [Checkpoint].checkpiontid 
        ) AS UC_Lat_Long
    ) as distance 
where 
    Day(distance.[day]) = 6 
    AND MONTH (distance.[day]) = 9 
    AND YEAR (distance.[day]) = 2011 
group by 
    distance.Userid, 
    distance.[day]

如何在SQL查询中将我的坐标划分为经度和纬度

1 个答案: