我被要求修改现有网站，它仍然使用PHP5.3和旧版本的PHPmyDirectory，代码有点乱。
我正在尝试修改它，只显示两列中的城市列表。我试图将它作为一个表格，因为它看起来最简单，但我也可以将结果拉到并排的div中，因为列出的城市从未超过26个（所以上半部分或前13部分，其余的在div二。）。
这是现有的原始代码（我知道它不是mysqli，但我们很快就会重做这个网站，所以现在尝试重做一百万页的代码是没有意义的）：
function create_service_area($title) {
global $listing;
$sql = "SELECT state_id, city_id FROM " .T_LISTINGS_CITIES. " WHERE listing_id = {$listing['id']} " ;
$result = query($sql);
if(!$result){
$output = "<p>Call for Service Area!</p>";
}
else {
$output = "<p>";
$result_array = array();
while ($service = fetch_array($result))
{
$sql2 = "SELECT title FROM " .T_LOCATIONS. " WHERE id = {$service['city_id']} " ;
$result2 = query($sql2);
if(!$result2){
break;
} else {
while ($service2 = fetch_array($result2))
{
$output .= "{$service2['title']}";
$title_array = explode(',', $service2['title']);
$result_array[] = $title_array;
}
$output .= "<br/>";
}
}
if($listing['custom_103'] =="Yes") {
$output .= "<b>".$title." will travel for an additional fee!</b></p>";
} else {
$output .="</p>";
}
}
return $output;
}
目前的情况如下：Current Site
这是我试图做的事情：
function create_service_area($title) {
global $listing;
$sql = "SELECT state_id, city_id FROM " .T_LISTINGS_CITIES. " WHERE listing_id = {$listing['id']} " ;
$result = query($sql);
if(!$result){
$output = "<p>Call for Service Area!</p>";
}
else {
$result_array = array();
while ($service = fetch_array($result)) {
$sql2 = "SELECT title FROM " .T_LOCATIONS. " WHERE id = {$service['city_id']} " ;
$result2 = query($sql2);
$i=0;
if(!$result2) {
break;
}
else {
while ($service2 = fetch_array($result2)) {
$output .= "{$service2['title']}";
$title_array = explode(',', $service2['title']);
$result_array[] = $title_array;
$i++;
}
echo "<table>";
for ($j=0; $j<$i; $j=$j+2) {
echo "<tr>";
echo "<td>".$title_array[$j]."</td><td>".$title_array[$j+1]."</td>";
echo "</tr>";
}
echo "</table>";
}
}
if($listing['custom_103'] =="Yes") {
$output .= "<p><b>".$title." will travel for an additional fee!</b></p>";
}
else {
$output .="";
}
}
return $output;
}
这就是我得到的：DEV site
我是一个PHP新手，我的理解非常参差不齐，但我已经尝试了一些我在这里找到的不同解决方案，并且无法让它们发挥作用。我确定我错过了一些明显的东西。
感谢您的任何指示！
答案 0 :(得分：1)
如果我弄错了你应该改变你的
else {
$output = "<p>";
$result_array = array();
while ($service = fetch_array($result))
{
$sql2 = "SELECT title FROM " .T_LOCATIONS. " WHERE id = {$service['city_id']} " ;
$result2 = query($sql2);
if(!$result2){
break;
} else {
while ($service2 = fetch_array($result2))
{
$output .= "{$service2['title']}";
$title_array = explode(',', $service2['title']);
$result_array[] = $title_array;
}
$output .= "<br/>";
}
}
if($listing['custom_103'] =="Yes") {
$output .= "<b>".$title." will travel for an additional fee!</b></p>";
} else {
$output .="</p>";
}
}
与
else {
$output = "<table>";
$result_array = array();
$even_odd=true;
while ($service = fetch_array($result))
{
$sql2 = "SELECT title FROM " .T_LOCATIONS. " WHERE id = {$service['city_id']} " ;
$result2 = query($sql2);
if(!$result2){
break;
} else {
$output .= "";
while ($service2 = fetch_array($result2))
{
if ($even_odd) {
$output .= '<tr><td>'."{$service2['title']}".'</td>';
$even_odd=false;
} else {
$output .= '<td>'."{$service2['title']}".'</td></tr>';
$even_odd=true;
}
$output .= "{$service2['title']}";
$title_array = explode(',', $service2['title']);
$result_array[] = $title_array;
}
}
}
if($listing['custom_103'] =="Yes") {
$output .= "<b>".$title." will travel for an additional fee!</b></p>";
} else {
if (!$even_odd)$output .="<td></td></tr>";
$output .="</table>";
}
}
答案 1 :(得分：1)
试试这个，我当然无法测试，因为我无法访问正在加载的数据。
echo "<table>";
$result_array = array();
while ($service = fetch_array($result))
{
//this will loop multiple times. 7 times for Tony S. in the example.
$sql2 = "SELECT title FROM " .T_LOCATIONS. " WHERE id = {$service['city_id']} " ;
$result2 = query($sql2);
$i=0;
if(!$result2)
{
break;
}
else
{
while ($service2 = fetch_array($result2))
{
$title_array = explode(',', $service2['title']);
$result_array[] = $title_array;
$i++;
}
}
}
for ($j=0; $j < count($result_array); $j++)
{
if ($j % 2 == 0)
{
echo "<tr>";
}
echo "<td>".$result_array[$j][0]." (".$result_array[$j][1].")</td>";
if ($j % 2 == 0)
{
echo "</tr>";
}
if ($j % 2 == 1 && $j == count($result_array)-1)
{
echo "<td></td></tr>";
}
}
echo "</table>";
粘贴并替换这些行：
if(!$result){
$output = "<p>Call for Service Area!</p>";
}
else {
.... PASTE IN HERE ....
}
答案 2 :(得分：0)
基于Kim的代码，我能够使用一些修订版。我也取消了div的表格，因为它对我来说似乎不那么混乱，看起来桌面造型在某种程度上干扰了。
function create_service_area($title) {
global $listing;
$sql = "SELECT state_id, city_id FROM " .T_LISTINGS_CITIES. " WHERE listing_id = {$listing['id']} " ;
$result = query($sql);
if(!$result){
$output = "<p>Call for Service Area!</p>";
} else {
$output = "<div>";
//$result_array = array();
$even_odd=true;
while ($service = fetch_array($result))
{
$sql2 = "SELECT title FROM " .T_LOCATIONS. " WHERE id = {$service['city_id']} " ;
$result2 = query($sql2);
if(!$result2){
break;
} else {
$output .= "{$service2['title']}";
$title_array = explode(',', $service2['title']);
$result_array[] = $title_array;
while ($service2 = fetch_array($result2))
{
if ($even_odd) {
$output .= '<div style="float:left;width:50%;">'."{$service2['title']}".'</div>';
$even_odd=false;
} else {
$output .= '<div style="float:right;width:50%;">'."{$service2['title']}".'</div>';
$even_odd=true;
}
}
}
}
if($listing['custom_103'] =="Yes") {
$output .= "<div style='clear:both;width:90%;float:none;'><p><b>".$title." will travel for an additional fee!</b></p></div>";
} else {
}
}
return $output;
}
非常感谢Kim和Mouser！