我有下面提到的数据。我希望得到最大的开始消息和相应的最小或成功消息。
启动消息表ID1 Timestamp_start_msg_recieved date jobid message time in seconds
1234 5/14/2014 10:02:29 5/14/2014 abc start 262
1234 5/14/2014 10:02:31 5/14/2014 abc start 264
1234 5/14/2014 10:02:45 5/14/2014 abc start 278
1234 5/14/2014 10:02:50 5/14/2014 abc start 285
1234 5/14/2014 10:09:04 5/14/2014 abc start 165
1234 5/14/2014 10:09:06 5/14/2014 abc start 2167
1234 5/14/2014 10:09:16 5/14/2014 abc start 2180
1234 5/14/2014 10:09:26 5/14/2014 abc start 2190
1234 5/14/2014 11:45:11 5/14/2014 abc start 8767
1234 5/14/2014 16:48:20 5/14/2014 abc start 878
1234 5/14/2014 19:02:52 5/14/2014 abc start 687
5678 5/14/2014 22:02:52 5/14/2014 pqr start 501
5678 5/14/2014 23:10:40 5/14/2014 pqr start 200
ID1 Timestamp_success_msg_recieved date jobid message time in seconds
1234 5/14/2014 10:02:52 5/14/2014 abc successful 290
1234 5/14/2014 10:09:32 5/14/2014 abc successful 4280
1234 5/14/2014 11:45:15 5/14/2014 abc successful 8774
1234 5/14/2014 11:45:18 5/14/2014 abc successful 8777
1234 5/14/2014 11:45:19 5/14/2014 abc successful 8778
1234 5/14/2014 11:45:25 5/14/2014 abc successful 8784
1234 5/14/2014 16:48:22 5/14/2014 abc successful 880
1234 5/14/2014 19:03:00 5/14/2014 abc successful 699
5678 5/14/2014 22:03:00 5/14/2014 pqr successful 250
5678 5/19/2014 14:00:16 5/19/2014 pqr successful 400
ID1 IMESTAMP_for_start_message TIMESTAMP_for_success_message Date Jobid msg msg start_secs success_secs
1234 5/14/2014 10:02:50 5/14/2014 10:02:52 5/14/2014 abc start success 262 290
1234 5/14/2014 10:09:26 5/14/2014 10:09:32 5/14/2014 abc start success 2190 4280
1234 5/14/2014 11:45:11 5/14/2014 11:45:25 5/14/2014 abc start success 8767 8784
1234 5/14/2014 16:48:20 5/14/2014 16:48:22 5/14/2014 abc start success 878 880
1234 5/14/2014 19:02:52 5/14/2014 19:03:00 5/14/2014 abc start success 687 699
5678 5/14/2014 22:02:52 5/14/2014 22:03:00 5/14/2014 pqr start success 501 699
5678 5/14/2014 23:10:40 null 5/14/2014 pqr start success 250 null
5678 null 5/19/2014 14:00:16 5/19/2014 pqr null success null 400
我正在寻找Max of start message和start_secs以配对min of success消息和success_secs。使用WITH子句尝试使用临时表，也使用自连接方法。下面是我的查询，但WITH子句查询返回表中整体数据的MIN。
使用的查询：
WITH DATA AS
(SELECT MIN(smt.column13) timestamp_for_success_message
FROM success_table1 smt, start_table2 b
WHERE
(SMT.id1 = b.id1)
AND (SMT.jobid = b.jobid)
AND (SMT.timestamp_for_success_message_recieved >= b.timestamp_for_start_message_recieved)
)
SELECT distinct a.timestamp_for_success_message_recieved,
b.timestamp_for_start_message_recieved,
b.id1,
b.jobid
FROM data a,
start_table2 b
order by b.timestamp_start_message_recieved, a.timestamp_for_success_message_recieved, b.jobid, b.id1;
答案 0 :(得分：0)
编辑：根据OP的反馈，查询对于实时数据失败。这可能是由于
GROUP BY (TRUNC(TIMESTAMP_for_start_message, 'MI'))
未正确分组＆＃34; id1＆＃34;和＆＃34; jobID＆＃34;。
对于样本数据，以下工作
WITH
LatestStart AS (
SELECT
MAX(TIMESTAMP_for_start_message) TIMESTAMP_for_start_message
FROM StartMessageTable
GROUP BY (TRUNC(TIMESTAMP_for_start_message, 'MI'))
),
LatestStartEarliestSuccess AS (
SELECT
LS.TIMESTAMP_for_start_message
, (SELECT MIN(TIMESTAMP_success_msg_received)
FROM SuccessMessageTable
WHERE
(id1 = StMT.id1)
AND (someDate = StMT.someDate)
AND (jobID = StMT.jobID)
AND (TIMESTAMP_success_msg_received >= StMT.TIMESTAMP_for_start_message)) TIMESTAMP_for_success_message
FROM LatestStart LS
JOIN StartMessageTable StMT
ON LS.TIMESTAMP_for_start_message = StMT.TIMESTAMP_for_start_message
),
Detail AS (
SELECT
StMT.id1
, LSES.TIMESTAMP_for_start_message
, LSES.TIMESTAMP_for_success_message
, StMT.jobID
, 'start' msgStart
, 'success' msgSuccess
, StMT.time_in_seconds start_secs
, SuMT.time_in_seconds success_secs
FROM LatestStartEarliestSuccess LSES
JOIN StartMessageTable StMT
ON LSES.TIMESTAMP_for_start_message = StMT.TIMESTAMP_for_start_message
LEFT JOIN SuccessMessageTable SuMT
ON LSES.TIMESTAMP_for_success_message = SuMT.TIMESTAMP_success_msg_received
ORDER BY LSES.TIMESTAMP_for_start_message
)
SELECT
* FROM Detail
;
除了＆＃34; start_secs＆＃34;中的第一个和最后一个值列 - 但是，它似乎偏离了样本输入。
SQL Fiddle
编辑： IIF 各自的＆＃34;时间戳＆＃34;和＆＃34;第二＆＃34;值-across tables-正确参考时间点，用于组合＆＃34; id1＆＃34;和＆＃34; jobID＆＃34;，以下提供了另一个起点：
SELECT DISTINCT
id1
, jobID
, message
-- , TO_CHAR(TIMESTAMP_for_start_message, 'YYYY-MM-DD HH24:MI:SS') timestamp
, TO_CHAR(TIMESTAMP_for_start_message - NUMTODSINTERVAL(time_in_seconds, 'SECOND'), 'YYYY-MM-DD HH24:MI:SS') job_start_time
-- , time_in_seconds
FROM StartMessageTable
UNION ALL
SELECT DISTINCT
id1
, jobID
, message
-- , TO_CHAR(TIMESTAMP_success_msg_received, 'YYYY-MM-DD HH24:MI:SS') timestamp
, TO_CHAR(TIMESTAMP_success_msg_received - NUMTODSINTERVAL(time_in_seconds, 'SECOND'), 'YYYY-MM-DD HH24:MI:SS') job_start_time
-- , time_in_seconds
FROM SuccessMessageTable
ORDER BY id1, jobID, 4, message;
但是，使用LEAD方法（在此问题的另一个答案中给出）返回通缉，可能不值得进一步研究该选项。
答案 1 :(得分：0)
对于样本数据，以下也适用
WITH
RawData AS (
SELECT
id1
, jobID
, message
, TIMESTAMP_for_start_message timeStamp
, time_in_seconds
FROM StartMessageTable
UNION ALL
SELECT
id1
, jobID
, message
, TIMESTAMP_success_msg_received
, time_in_seconds
FROM SuccessMessageTable
ORDER BY id1, jobID, 4
),
Detail AS (
SELECT
id1
, jobID
, message message1
, LEAD (message, 1) OVER (ORDER BY id1, jobID, timeStamp) message2
, timeStamp timeStamp1
, LEAD (timeStamp, 1) OVER (ORDER BY id1, jobID, timeStamp) timeStamp2
, time_in_seconds secs1
, LEAD (time_in_seconds, 1) OVER (ORDER BY id1, jobID, timeStamp) secs2
FROM RawData
)
SELECT
id1
, timeStamp1 TIMESTAMP_for_start_message
, timeStamp2 TIMESTAMP_for_success_message
, jobID
, 'start' msgStart
, 'success' msgSuccess
, secs1 start_secs
, secs2 success_secs
FROM Detail
WHERE (message1 = 'start' AND message2 = 'successful') OR message2 IS NULL
ORDER BY timeStamp1
;
对“start_secs”列中的第一个和最后一个值有相同的警告 SQL Fiddle