我正在开发一个自动化脚本[使用selenium和python],它应该执行以下操作
我不想对值为“0”的列的xpath进行硬编码,而是动态地查找它并继续。
以下代码是我写的
trows = table1.find_elements_by_xpath("//table[@id='ambassadors-for-assignment']/tbody/tr")
row_count = len(trows)
tcols = trows.find_elements_by_xpath("//table[@id='ambassadors-for-assignment']/tbody/tr/td")
col_count = len(tcols)
first_part = "//table[@id=ambassadors-for-assignment']/tbody/tr["
second_part = "]/td["
third_part = "]"
for i in range(1, len(row_count)):
for j in range(1, len(col_count)):
final_xpath = first_part+i+second_part+j+third_part
HTML文件结构
<tbody>
<tr>
<td> james </td>
<td> watson </td>
<td> 10 | 5 </td>
<td>
<div class="btn-group" role="group">
<button class="btn btn-success" type="button">
<i class="fa fa-plus"></i>
</button>
<button class="btn btn-danger" type="button">
<i class="fa fa-minus"></i>
</button>
</div>
</td>
</tr>
....
我的HTML文件有n行,上面给出了列。正如我所提到的,我想阅读第三列值[即10 | 5]看看它的0是否[仅考虑第三列中的第一项],然后在下一栏中点击[btn btn-success]按钮。
任何进一步行动的指示都将不胜感激!
我将在评论部分提供实际HTML文件的链接
答案 0 :(得分:0)
我不想硬编码具有值&#34; 0&#34;的列的xpath。
from selenium import webdriver
import re
driver = webdriver.PhantomJS()
driver.set_window_size(1120, 550) #For bug
driver.get("http://localhost:8000")
pattern = r"""
\s* #Match whitespace, 0 or more times, followed by...
(\d+) #a digit, one or more times, captured, followed by
\s* #whitespace, 0 or more times, followed by...
[|] #vertical bar, followed by...
\s* #whitespace, 0 or more times, followed by...
\d+ #a digit, one or more times
"""
regex = re.compile(pattern, re.X)
table = driver.find_element_by_id('ambassadors-for-assignment')
trs = table.find_elements_by_tag_name('tr')
for tr in trs:
tds = tr.find_elements_by_tag_name('td')
for td in tds:
match_obj = re.search(regex, text)
if match_obj and match_obj.group(1) == '0':
success_button = tr.find_element_by_css_selector('button.btn-success')
print success_button.get_attribute('type')
success_button.click()
re.match(pattern,string,flags = 0)
如果字符串开头的零个或多个字符与正则表达式模式匹配,则返回相应的匹配对象。如果字符串与模式不匹配,则返回None;请注意,这与零长度匹配不同。
请注意,即使在MULTILINE模式下,re.match()也只会匹配字符串的开头而不是每行的开头。
如果要在字符串中的任何位置找到匹配项,请改用search()(另请参阅search()与match())。
https://docs.python.org/3/library/re.html#module-re
<强> == 强>
这里是xpath,我认为它更符合你要做的事情,即给定一个列,向下看行0的值:
from selenium import webdriver
import re
driver = webdriver.PhantomJS()
driver.set_window_size(1120, 550) #For bug
driver.get("http://localhost:8000")
pattern = r"""
\s* #Match whitespace, 0 or more times, followed by...
(\d+) #a digit, one or more times, captured, followed by
\s* #whitespace, 0 or more times, followed by...
[|] #vertical bar, followed by...
\s* #whitespace, 0 or more times, followed by...
\d+ #a digit, one or more times
"""
regex = re.compile(pattern, re.X)
trs = driver.find_elements_by_xpath('//table[@id="ambassadors-for-assignment"]/tbody/tr')
target_columns = [3, 4]
for target_column in target_columns:
for tr in trs:
target_column_xpath = './td[{}]'.format(target_column) #VARY COLUMN HERE ***
td = tr.find_element_by_xpath(target_column_xpath)
match_obj = re.match(regex, td.text)
if match_obj and match_obj.group(1) == '0':
button_xpath = './/button[contains(concat(" ", normalize-space(@class), " "), " btn-success ")]'
success_button = tr.find_element_by_xpath(button_xpath)
#success_button.click()
print "column {}:".format(target_column)
print match_obj.group(0)
print success_button.get_attribute('class')
print
输出将如下所示,具体取决于您尝试与正则表达式匹配的文本:
column 3:
0 | 5
btn btn-success
column 4:
0 | 61
btn btn-success
但在我看来,必须在xpath中使用以下内容:
'[contains(concat(" ", normalize-space(@class), " "), " btn-success ")]'
匹配一个类,意味着使用xpath不是这样做的方法。 python方法:
find_element_by_csss_selector('button.btn-success')
......会更简洁明了地做同样的事情。