Question

目标：人可以关注任何其他人或组织。

/**
 * PersonFollow schema:
    CREATE TABLE `person_follows` (
        `id` int(11) NOT NULL AUTO_INCREMENT,
        `person_id` int(11) DEFAULT NULL,
        `table_id` int(11) DEFAULT NULL,
        `table_name` varchar(255) DEFAULT NULL,
        PRIMARY KEY (`id`),
        KEY `i_person_id` (`person_id`),
        KEY `i_table_id` (`table_id`)
    ) ENGINE=MyISAM AUTO_INCREMENT=1 DEFAULT CHARSET=utf8 COLLATE=utf8_general_ci;
 */

class PersonFollow extends AppModel {
    public $belongsTo = array(
        'Person' => array(
            'foreignKey' => 'person_id',
        ),
        'FollowPerson' => array(
            'className' => 'Person',
            'foreignKey' => 'table_id',
            //'conditions' => array('PersonFollow.table_name' => 'persons'), // tried this
        ),
        'FollowOrganization' => array(
            'className' => 'Organization',
            'foreignKey' => 'table_id',
            //'conditions' => array('PersonFollow.table_name' => 'organizations'), // tried this
        ),
    );
}

class Person extends AppModel {
    public $hasMany = array(
        'Following' => array(
            'className' => 'PersonFollow',
            'dependent' => true,
        ),
        'Follower' => array(
            'className' =>'PersonFollow',
            'foreignKey' => 'table_id',
            'conditions' => array('Follower.table_name' => 'persons'),
            'dependent' => true
        ),
    );
}

class Organization extends AppModel {
    public $hasMany = array(
        'Follower' => array(
            'className' =>'PersonFollow',
            'foreignKey' => 'table_id',
            'conditions' => array('Follower.table_name' => 'organizations'),
            'dependent' => true
            /* Tried this
            'foreignKey' => false,
            'finderQuery' => 'SELECT `PersonFollow`.*
                FROM `person_follows` as `PersonFollow`
                WHERE `PersonFollow`.`table_id` = {$__cakeForeignKey__$}
                AND `PersonFollow`.`table_name` = "organizations"',
            */
        )
    );
}

$following = $this->Person->find('all', array(
    'contain' => array('Following' => array('FollowPerson','FollowOrganization')),
    'conditions' => array('Person.id' => 1234),
));

$following的结果返回all在table_id上匹配之后，并且不使用table_name条件。我正在尝试使用FollowOrganization，其中PersonFollow.table_name ='organizations'，对于FollowPerson，PersonFollow.table_name ='persons'也是如此。似乎$hasMany仅使用'foreignKey'而不是'条件'。我错过了什么？

CakePHP在hasMany中使用foreignKey和条件

0 个答案: