Question

如果string = Firstname Lastname (email1@place.edu) Firstname2 Lastname2 (email2@place.edu) 我想创建一个新的字符串email1@place.edu,email2@place.edu

我试过

string= string.partition('(')[-1].partition(')')[0]

然后我得到email1@place.edu) Firstname2 Lastname2 (email2@place.edu

如何拆分此字符串？

Answer 1

string.split()

你可以通过传递参数告诉Python你对split()的看法。 see the docs for more functionality

split()方法会为您留下list，您可以在此情况下使用for loop或list comprehension来迭代访问每个项目。

在将问题（特定的）发布到SO之前，您应该始终查看Google和文档，以便获得最佳反馈。

编辑：

如果您只是尝试访问字符串b / w括号，则可以使用正则表达式或python＆＃39; s find() method

string = "Firstname Lastname (email1@place.edu) Firstname2 Lastname2 (email2@place.edu)"
stringlist = string.split()
email_addresses = [item[1:-1] for item in stringlist if "(" in item and ")" in item]

Answer 2

使用正则表达式。

import re 
regexp_pattern = '\([^\(\r\n]*\)'
st = "Firstname Lastname (email1@place.edu) Firstname2 Lastname2 (email2@place.edu)"
a = re.findall(regexp_pattern, st) #this gives you the list ['(email1@place.edu)','(email2@place.edu)']
b = ''.join(a)[1:-1] #this gives you the string 'email1@place.edu)(email2@place.edu'
b.replace(")(", ",") #this gives you the string 'email1@place.edu,email2@place.edu'

当然，如果你更喜欢（我这样做），你可以做得更短：

import re 
regexp_pattern = '\([^\(\r\n]*\)'
st = "Firstname Lastname (email1@place.edu) Firstname2 Lastname2 (email2@place.edu)"
''.join(re.findall(regexp_pattern, st))[1:-1].replace(")(", ",")

从python中的多组括号中的字符串中提取文本

2 个答案: