我希望有人可以帮助我。
我有以下5个表：
CustomerID CustomerName
------- ------------
1 ABC Bank
2 Chase Bank
OrderTypeID OrderTypeName
---------- ------------
1 Assignment
2 LienRelease
ActivityID ActivityName
---------- ------------
1 Received
2 Keyed
3 Printed
4 Delivered To Customer
OrderID CustomerID OrderTypeID LoanNumber
---------- ------------ ----------- ----------
1 1 1 45584565
2 1 1 45566856
3 1 1 45565584
4 1 1 45588545
OrderID ActivityID ActivityDate
---------- ----------- ----------
1 1 2007-04-16 8:34:00 AM
1 2 2007-04-16 9:22:00 AM
1 3 2007-04-16 9:51:00 AM
1 4 2007-04-16 4:14:00 PM
2 1 2007-04-16 8:34:00 AM
2 3 2014-12-16 10:33:09 AM
3 1 2007-04-16 8:34:00 AM
3 2 2007-04-16 9:22:00 AM
3 3 2007-04-16 9:51:00 AM
3 4 2007-04-16 4:14:00 PM
4 1 2007-04-16 8:34:00 AM
4 2 2007-04-16 9:22:00 AM
4 3 2007-04-16 9:51:00 AM
为保护目的，信息已被更改。所以说我需要能够按客户列出所有订单以及时间差（以分钟为单位）： - “收到”到“键入”为[TurnTime1] - “键入”到“已打印”为[TurnTime2] - “打印”到“已交付”为[TurnTime3] - “收到”至“已交付”为[TurnTime4] 我还需要返回CustomerName，OrderTypeName，LoanNumber，TurnTime1，TurnTime2，TurnTime3和TurnTime4。我相信我很接近，但是，我尝试了两种不同的方式，这两种方式都不正确，而且我被卡住了。第一个选项，仅包含4行，其值为＆＃34; 0＆＃34;每个TurnTime专栏。第二个选项包括超过600行。我相信这应该只返回11行数据，也许还有一些额外的行，数据不符合规定。以下是我到目前为止的情况：
SELECT DISTINCT tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblOrder.LoanNumber,
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime1],
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime2],
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime3],
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime4]
FROM tblOrder
INNER JOIN tblOrderActivity
ON tblOrder.OrderID = tblOrderActivity.OrderID
INNER JOIN tblActivity
ON tblOrderActivity.ActivityID = tblActivity.ActivityID
INNER JOIN tblOrderType
ON tblOrderType.OrderTypeID = tblOrder.OrderTypeID
INNER JOIN tblCustomer
ON tblCustomer.CustomerID = tblOrder.CustomerID
WHERE EXISTS (SELECT * FROM tblActivity WHERE ActivityName IS NOT NULL)
GROUP BY tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblorder.LoanNumber, tblOrderActivity.ActivityDate;
SELECT DISTINCT tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblOrder.LoanNumber,
(DATEPART(mi,(TT2.ActivityDate - TT1.ActivityDate))) AS [TurnTime1],
(DATEPART(mi,(TT3.ActivityDate - TT2.ActivityDate))) AS [TurnTime2],
(DATEPART(mi,(TT4.ActivityDate - TT3.ActivityDate))) AS [TurnTime3],
(DATEPART(mi,(TT4.ActivityDate - TT1.ActivityDate))) AS [TurnTime4]
FROM tblOrder
INNER JOIN tblOrderActivity AS TT1
ON tblOrder.OrderID = TT1.OrderID
INNER JOIN tblOrderActivity AS TT2
ON tblOrder.OrderID = TT2.OrderID
INNER JOIN tblOrderActivity AS TT3
ON tblOrder.OrderID = TT3.OrderID
INNER JOIN tblOrderActivity AS TT4
ON tblOrder.OrderID = TT4.OrderID
INNER JOIN tblActivity AS TA1
ON TT1.ActivityID = TA1.ActivityID
INNER JOIN tblActivity AS TA2
ON TT2.ActivityID = TA2.ActivityID
INNER JOIN tblActivity AS TA3
ON TT3.ActivityID = TA3.ActivityID
INNER JOIN tblActivity AS TA4
ON TT4.ActivityID = TA4.ActivityID
INNER JOIN tblOrderType
ON tblOrderType.OrderTypeID = tblOrder.OrderTypeID
INNER JOIN tblCustomer
ON tblCustomer.CustomerID = tblOrder.CustomerID
WHERE EXISTS (SELECT * FROM tblActivity WHERE ActivityName IS NOT NULL)
GROUP BY tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblorder.LoanNumber, TT1.ActivityDate,
TT2.ActivityDate, TT3.ActivityDate, TT4.ActivityDate;
答案 0 :(得分：1)
这个怎么样： SQL Fiddle
MS SQL Server 2008架构设置：
create table tblCustomer
(
CustomerID int,
CustomerName varchar(max)
)
INSERT INTO tblCustomer
VALUES
( 1, 'ABC Bank'),
( 2, 'Chase Bank')
create table tblOrderType
(
OrderTypeID int,
OrderTypeName varchar(max)
)
INSERT INTO tblOrderType
VALUES
( 1, 'Assignment'),
( 2, 'LienRelease')
create table tblActivity
(
ActivityID int,
ActivityName varchar(max)
)
INSERT INTO tblActivity
VALUES
( 1, 'Received'),
( 2, 'Keyed'),
( 3, 'Printed'),
( 4, 'Delivered To Customer')
CREATE TABLE tblOrder
(
OrderID int,
CustomerID int,
OrderTypeID int,
LoanNumber int
)
INSERT INTO tblOrder
VALUES
( 1, 1, 1, 45584565),
( 2, 1, 1, 45566856),
( 3, 1, 1, 45565584),
( 4, 1, 1, 45588545)
CREATE TABLE tblOrderActivity
(
OrderID int,
ActivityID int,
ActivityDate DateTime
)
INSERT INTO tblOrderActivity
VALUES
(1, 1, '2007-04-16 8:34:00 AM'),
(1, 2, '2007-04-16 9:22:00 AM'),
(1, 3, '2007-04-16 9:51:00 AM'),
(1, 4, '2007-04-16 4:14:00 PM'),
(2, 1, '2007-04-16 8:34:00 AM'),
(2, 3, '2014-12-16 10:33:09 AM'),
(3, 1, '2007-04-16 8:34:00 AM'),
(3, 2, '2007-04-16 9:22:00 AM'),
(3, 3, '2007-04-16 9:51:00 AM'),
(3, 4, '2007-04-16 4:14:00 PM'),
(4, 1, '2007-04-16 8:34:00 AM'),
(4, 2, '2007-04-16 9:22:00 AM'),
(4, 3, '2007-04-16 9:51:00 AM')
查询1 ：
SELECT C.CustomerName,O.OrderId, OT.OrderTypeName, O.LoanNumber,
(DATEDIFF(mi, Received.ActivityDate, Keyed.ActivityDate)) AS [TurnTime1],
(DATEDIFF(mi, Keyed.ActivityDate, Printed.ActivityDate)) AS [TurnTime2],
(DATEDIFF(mi, Printed.ActivityDate, Delivered.ActivityDate)) AS [TurnTime3],
(DATEDIFF(mi, Received.ActivityDate, Delivered.ActivityDate)) AS [TurnTime4]
FROM tblCustomer C
INNER JOIN tblOrder O
ON O.CustomerId = C.CustomerId
INNER JOIN tblOrderType OT
ON OT.OrderTypeID = O.OrderTypeID
INNER JOIN tblOrderActivity Received
ON Received.OrderID = O.OrderID AND Received.ActivityId = 1
LEFT JOIN tblOrderActivity Keyed
ON Keyed.OrderID = O.OrderID AND Keyed.ActivityId = 2
LEFT JOIN tblOrderActivity Printed
ON Printed.OrderID = O.OrderID AND Printed.ActivityId = 3
LEFT JOIN tblOrderActivity Delivered
ON Delivered.OrderID = O.OrderID AND Delivered.ActivityId = 4
<强> Results ：
| CUSTOMERNAME | ORDERID | ORDERTYPENAME | LOANNUMBER | TURNTIME1 | TURNTIME2 | TURNTIME3 | TURNTIME4 |
|--------------|---------|---------------|------------|-----------|-----------|-----------|-----------|
| ABC Bank | 1 | Assignment | 45584565 | 48 | 29 | 383 | 460 |
| ABC Bank | 2 | Assignment | 45566856 | (null) | (null) | (null) | (null) |
| ABC Bank | 3 | Assignment | 45565584 | 48 | 29 | 383 | 460 |
| ABC Bank | 4 | Assignment | 45588545 | 48 | 29 | (null) | (null) |
如果您需要删除包含NULL的行，只需将LEFT JOIN更改为INNER JOIN
答案 1 :(得分：0)
<强> SQL Fiddle Demo
您可以使用case based aggregation减法来获得客户每个订单的活动之间的时间差异。
select C.CustomerNAme, OT.OrderTypeName, O.LoanNumber,
max ( case when OA.ActivityID =2 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =1 then datediff(minute,0,OA.ActivityDate) end) as TurnTime1,
max ( case when OA.ActivityID =3 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =2 then datediff(minute,0,OA.ActivityDate) end) as TurnTime2,
max ( case when OA.ActivityID =4 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =3 then datediff(minute,0,OA.ActivityDate) end) as TurnTime3,
max ( case when OA.ActivityID =4 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =1 then datediff(minute,0,OA.ActivityDate) end) as TurnTime4
FROM tblCustomer C
JOIN tblOrder O
on C.CustomerID = O.CustomerID
JOIN tblOrderActivity OA
on OA.OrderID = O.OrderID
JOIN tblOrderType OT
on OT.OrderTypeID = O.OrderTypeID
GROUP BY C.CustomerName, OT.OrderTypeName, O.LoanNumber
答案 2 :(得分：0)
这应该只是根据表活动为您想要的每个组创建连接表的简单问题。请注意，我假设活动只能执行一次。
Select tblCustomer.CustomerName,
tblOrderType.OrderTypeName,
tblOrder.LoanNumber,
DATEDiff(mi,tblOrderReceived.ActivityDate, tblOrderKeyed.ActivityDate) AS [TurnTime1],
DATEDiff(mi,tblOrderKeyed.ActivityDate, tblOrderPrinted.ActivityDate) AS [TurnTime2],
DATEDiff(mi,tblOrderPrinted.ActivityDate, tblOrderDelivered.ActivityDate) AS [TurnTime3],
DATEDiff(mi,tblOrderReceived.ActivityDate, tblOrderDelivered.ActivityDate) AS [TurnTime4]
From tblOrder
INNER JOIN tblOrderType
ON tblOrderType.OrderTypeID = tblOrder.OrderTypeID
INNER JOIN tblCustomer
ON tblCustomer.CustomerID = tblOrder.CustomerID
Left Outer Join tblOrderActivity tblOrderReceived
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblOrderActivity tblOrderKeyed
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblOrderActivity tblOrderPrinted
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblOrderActivity tblOrderDelivered
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblActivity
ON tblOrderReceived.ActivityID = tblActivity.ActivityID
OR tblOrderKeyed.ActivityID = tblActivity.ActivityID
OR tblOrderPrinted.ActivityID = tblActivity.ActivityID
OR tblOrderDelivered.ActivityID = tblActivity.ActivityID
Where tblOrderReceived.ActivityID = 1
And tblOrderKeyed.ActivityID = 2
And tblOrderPrinted.ActivityID = 3
And tblOrderDelivered.ActivityID = 4
And tblOrder.OrderID In (Select ActivityMask.OrderID from tblOrderActivity ActivityMask)