要求快速通知许可（iOs 7）

Question

我如何在iOs 8和iOs7中请求权限。 我试过这个：

UIApplication.sharedApplication().registerForRemoteNotificationTypes(UIUserNotificationTypeBadge | UIUserNotificationTypeSound | UIUserNotificationTypeAlert)

但它不起作用。

这是我的代码，仅适用于iOS 8：

  if(UIApplication.instancesRespondToSelector(Selector("registerUserNotificationSettings:"))) {
            UIApplication.sharedApplication().registerUserNotificationSettings(UIUserNotificationSettings(forTypes: .Alert | .Sound, categories: nil))
        }

        else {

        }

Answer 1

夫特：

//-- Set Notification
if application.respondsToSelector("isRegisteredForRemoteNotifications")
{
    // iOS 8 Notifications
    application.registerUserNotificationSettings(UIUserNotificationSettings(forTypes: .Badge | .Sound | .Alert, categories: nil))
    application.registerForRemoteNotifications()
}else{
    // iOS < 8 Notifications
    application.registerForRemoteNotificationTypes(.Badge | .Sound | .Alert)
}

目标-C：

//-- Set Notification
if ([application respondsToSelector:@selector(isRegisteredForRemoteNotifications)]) 
{
       // iOS 8 Notifications
       [application registerUserNotificationSettings:[UIUserNotificationSettings settingsForTypes:(UIUserNotificationTypeSound | UIUserNotificationTypeAlert | UIUserNotificationTypeBadge) categories:nil]];

       [application registerForRemoteNotifications];
}
else
{
      // iOS < 8 Notifications
      [application registerForRemoteNotificationTypes:
                 (UIRemoteNotificationTypeBadge | UIRemoteNotificationTypeAlert | UIRemoteNotificationTypeSound)];
}

Answer 2

最近有些语法发生了变化。这对我有用。

if(UIApplication.instancesRespondToSelector(#selector(UIApplication.registerUserNotificationSettings(_:)))) {
        UIApplication.sharedApplication().registerUserNotificationSettings(UIUserNotificationSettings(forTypes:[.Badge , .Sound , .Alert], categories: nil))
        UIApplication.sharedApplication().registerForRemoteNotifications()
}