我有一个重要的问题。我正在创建一个iPhone应用程序。 我有一个带有goBack,goForward和reload的UIWebView(https://www.google.de/)。 现在,我想要一个按钮,例如条形按钮项目名为Home或Homepage,用于在此WebView中打开URL(https://www.google.de/),以返回主页。 我怎样才能做到这一点?我怎么能说"用于在WebView中打开链接的按钮?我要求回答。
// ViewController.h
#import <UIKit/UIKit.h>
@interface ViewController : UIViewController
@property (nonatomic, strong) IBOutlet UIWebView *site ;
@end
// ViewController.m
#import "ViewController.h"
@interface ViewController ()
@end
@implementation ViewController
-(IBAction)refresh:(id)sender; {
NSURL *url=[NSURL URLWithString: @"https://www.google.de/"]; NSURLRequest * requestURL=[NSURLRequest requestWithURL:url]; [_site loadRequest:requestURL];
}
- (void)viewDidLoad {
[self refresh:self];
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
}
- (void)didReceiveMemoryWarning {
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}
@end
答案 0 :(得分:2)
UIWebView
有方法goBack
和goForward
。您可以进行操作并将其与条形按钮绑定,以便随时返回。
- (IBAction)goBack:(id)sender {
[_site goBack];
}
- (IBAction)goForward:(id)sender {
[_site goForward];
}
- (IBAction)goHomepage:(id)sender {
NSURL *url=[NSURL URLWithString: @"https://www.google.de/"];
NSURLRequest *requestURL=[NSURLRequest requestWithURL:url];
[_site loadRequest:requestURL];
}
为了向您提供更多帮助,here's a tutorial on this,如果您不想阅读该教程,可以查看他们的source code from here!