Question

这是我的代码，它打印拥有ID_no的人的姓氏，该ID在下拉选项中。我想要的是在文本框中输出它，所以一旦选择了id_no，它将自动填充该字段：

<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "auth";

// Create connection
$conn = new mysqli("localhost", "root", "", "auth");
// Check connection
if ($conn->connect_error) {
 die("Connection failed: " . $conn->connect_error);
}

$sql = "SELECT id_no,fn,sn,mn from employee ORDER BY id_no asc";
$result = $conn->query($sql);
?>

<select name='id_no' onchange="changeSelect(this.value)">
   <?php while ($row = $result->fetch_array()) { ?>

 <option value="<?php echo($row['sn']);  ?>"   > 

       <?php echo($row['id_no']); ?> 

   </option> 
   <?php }  ?> 

</select>

<div id="demo"></div>
<script>
function changeSelect(value)
{
   document.getElementById("demo").innerHTML = value
}
</script>

我的问题是，我将把<input type="text">内容放在哪里？

Answer 1

<?php echo"<input type=text name=fullname size=50  value=$row[sn],$row[fn],$row[mn] required>";

是的，我做到了：）

选择下拉项后，如何在数据库中获取后填充文本字段

1 个答案: