使用setError编辑文本输入验证Android

Question

我通过检查空输入并调用setError来检查警报对话框中一组编辑文本的无效输入。但是在我当前的实现中，即使输入无效，对话框仍然会关闭。

每个编辑文本都添加了一个布尔检查，以防止在任何编辑文本将布尔值设置为false时解除对话框，如下所示：

      else if(TextUtils.isEmpty(strColour)) {
        colourText.setError("Please enter a value");
        entriesValid = false;

` 但是，尽管输入无效，对话仍然被驳回。

我的问题，这里的错误是什么，允许对话框关闭无效输入？

我在这一行if(entriesValid)设置了一个断点，以检查条件是否被触发但是它没有在此处中断，这意味着将跳过该检查。

这是完整的自定义对话框类：

public class MyMessageDialog  {

    public interface MyMessageDialogListener {
        public void onClosed(String ship, String scientist, String email, String volume, String color);
    }

@SuppressLint("NewApi") 
public static AlertDialog displayMessage(Context context, String title, String message, final MyMessageDialogListener listener){ 
    AlertDialog.Builder builder = new AlertDialog.Builder(context); 
    LayoutInflater inflater = LayoutInflater.from(context);
    builder.setTitle(title); 
    builder.setMessage(message); 
    final View layoutView = inflater.inflate(R.layout.custom_view, null);
    builder.setView(layoutView);
    builder.setPositiveButton("Ok", new DialogInterface.OnClickListener() { 
    @Override 
    public void onClick(DialogInterface dialog, int which) { 
        boolean entriesValid = true;
        // get the edit text values here and pass them back via the listener
        if(listener != null)
        {
        EditText shipText = (EditText)layoutView.findViewById(R.id.shipNameEditText);
        EditText scientistNameText = (EditText)layoutView.findViewById(R.id.scientistEditText);
        EditText scientistEmailText = (EditText)layoutView.findViewById(R.id.emailEditText);
        EditText volumeText = (EditText)layoutView.findViewById(R.id.volumeEditText);
        EditText colourText = (EditText)layoutView.findViewById(R.id.colourEditText);



        listener.onClosed(shipText.getText().toString(),
                scientistNameText.getText().toString(),
                scientistEmailText.getText().toString(),
                volumeText.getText().toString(),
                colourText.getText().toString());

        String strShipName = shipText.getText().toString();
        String strScientistName = scientistNameText.getText().toString();
        String strScientistEmail = scientistEmailText.getText().toString();
        String strVolume = volumeText.getText().toString();
        String strColour = colourText.getText().toString();
        if(TextUtils.isEmpty(strShipName)) {
            shipText.setError("Please enter a value");
            entriesValid = false;
         }
        else if(TextUtils.isEmpty(strShipName)) {
            shipText.setError("Please enter a value");
            entriesValid = false;
         }
        else if(TextUtils.isEmpty(strScientistName)) {
            scientistNameText.setError("Please enter a value");
            entriesValid = false;
         }
        else if(TextUtils.isEmpty(strScientistEmail)) {
            scientistEmailText.setError("Please enter a value");
            entriesValid = false;
         }
        else if(TextUtils.isEmpty(strVolume)) {
            volumeText.setError("Please enter a value");
            entriesValid = false;
         }
        else if(TextUtils.isEmpty(strColour)) {
            colourText.setError("Please enter a value");
            entriesValid = false;
         }
        }
        if(entriesValid)
            dialog.dismiss(); 
        } 
        }); 
        builder.show(); 
        return builder.create();
    } 

}

Answer 1

不是将侦听器检查为null，而是添加try catch块。我没有尝试过这段代码。但我的想法是用try catch删除监听器块并相应地设置布尔标志。这样就变得简单了。

@SuppressLint("NewApi") 
        public static AlertDialog displayMessage(Context context, String title, String message, final MyMessageDialogListener listener){ 
            AlertDialog.Builder builder = new AlertDialog.Builder(context); 
            LayoutInflater inflater = LayoutInflater.from(context);
            builder.setTitle(title); 
            builder.setMessage(message); 
            final View layoutView = inflater.inflate(R.layout.custom_view, null);
            builder.setView(layoutView);
            builder.setPositiveButton("Ok", new DialogInterface.OnClickListener() { 
            @Override 
            public void onClick(DialogInterface dialog, int which) { 
                boolean entriesValid = true;
                // get the edit text values here and pass them back via the listener
               try
                {
                EditText shipText = (EditText)layoutView.findViewById(R.id.shipNameEditText);
                EditText scientistNameText = (EditText)layoutView.findViewById(R.id.scientistEditText);
                EditText scientistEmailText = (EditText)layoutView.findViewById(R.id.emailEditText);
                EditText volumeText = (EditText)layoutView.findViewById(R.id.volumeEditText);
                EditText colourText = (EditText)layoutView.findViewById(R.id.colourEditText);

                String strShipName = shipText.getText().toString();
                String strScientistName = scientistNameText.getText().toString();
                String strScientistEmail = scientistEmailText.getText().toString();
                String strVolume = volumeText.getText().toString();
                String strColour = colourText.getText().toString();

                if(TextUtils.isEmpty(strShipName)) {
                    shipText.setError("Please enter a value");
                    entriesValid = false;
                 }
                else if(TextUtils.isEmpty(strShipName)) {
                    shipText.setError("Please enter a value");
                    entriesValid = false;
                 }
                else if(TextUtils.isEmpty(strScientistName)) {
                    scientistNameText.setError("Please enter a value");
                    entriesValid = false;
                 }
                else if(TextUtils.isEmpty(strScientistEmail)) {
                    scientistEmailText.setError("Please enter a value");
                    entriesValid = false;
                 }
                else if(TextUtils.isEmpty(strVolume)) {
                    volumeText.setError("Please enter a value");
                    entriesValid = false;
                 }
                else if(TextUtils.isEmpty(strColour)) {
                    colourText.setError("Please enter a value");
                    entriesValid = false;
                 }
                }
    catch(Exception e)
    {
    entriesValid = false;
    }
                if(entriesValid)
                    dialog.dismiss(); 
                } 
                }); 
                builder.show(); 
                return builder.create();
            } 

更新 - 新解决方案 - 尝试并为我工作

public class Help_DialogScreen extends Dialog implements OnClickListener{
 Context context;
    public Help_DialogScreen(Context context) {
        super(context);
        // TODO Auto-generated constructor stub
        this.context=context;
    }

    @Override
      protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        requestWindowFeature(Window.FEATURE_NO_TITLE);
        setContentView(R.layout.help_homescreen);

        EditText tvGoToAddExpense = (EditText)findViewById(R.id.txtGoToAddExpense);

        Button btnTestCLick = (Button)findViewById(R.id.btnTestClick);

        btnTestCLick.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub
                Toast.makeText(context, "Click fired", Toast.LENGTH_SHORT).show();
                // I have used Toast to show that on click of button, dialog is not getting dismissed. You can add your code and do your logic here.
            }
        });


      }

    @Override
    public void onClick(DialogInterface dialog, int which) {

        dismiss();
    }

}

在您应该显示对话框的代码中，添加此代码

Help_DialogScreen cdd=new Help_DialogScreen(CURRENTACTIVITY.this);
                cdd.show();