Question

# program to test truth tables v2

import time 
import sys

x = 0

while x == 0:
    x = str(raw_input("Please enter True or False..."))
    x = x[0].upper()+ x[1:]

    if x == "True":  
        x = True
    elif x == "False":
        x = False
    else:
        print 'invalid input!'
        x = 0 # very difficult but this works now!

print x

y = 0

while y == 0:
    y = str(raw_input("Please enter True or False again..."))
    y = y[0].upper()+ y[1:]

    if y == "True":
        y = True
    elif y == "False":
        y = False
    else:
        print 'invalid input!'
        y = 0

problem = 0
while problem == 0:
    problem = input("Please enter number: \n1 for AND, 2 for OR, 3 for NAND, 4 for NOR...")
    if problem == 1:
        print "I'm thinking.."
        time.sleep(2.5) 
        print "the answer is..."
        time.sleep(1.0) 
        print x, "AND", y, "is", x and y 

    elif problem == 2:
        print "I'm thinking.."
        time.sleep(2.5)
        print "the answer is..."
        time.sleep(1)
        print x, "OR", y, "is", x or y

    elif problem == 3:
        print "I'm thinking.."
        time.sleep(2.5)
        print "the answer is..."
        time.sleep(1)
        print x, "NAND", y, "is", not(x and y) # not working for false/false or false/true

    elif problem == 4:
        print "I'm thinking.."
        time.sleep(2.5)
        print "the answer is..."
        time.sleep(0.5)
        print x, "NOR", y, "is", not(x or y) # not working for false/false
    else:
        print 'invalid input'
        problem = 0

我认为这个项目一旦我测试了所有组合，我发现第一个while循环中的elif存在问题。请参阅上一节中的注释。感谢任何帮助

Answer 1

你的第一个while循环中的问题是0 == False。把它翻译成翻译并看看。

Answer 2

这是我的猜测。你需要把你的布尔变成字符串。例如，在第一个while loop中，您将x设置为等于True和False而不是＆＃34; True＆＃34;并且＆＃34;错误。＆＃34;由于Python将布尔值True和False分别视为1和0，因此在False的情况下，while循环变量（x和y）保持等于零。每当用户输入False

时，您可能会重复此操作

试一试，看看。让我知道。无论你做什么，继续练习！你会得到它。

编辑：是的，这就是问题所在。这是您的工作代码。

import time 
import sys

x = 0

while x == 0:
    x = str(raw_input("Please enter True or False..."))
    #x = x[0].upper()+ x[1:]
    print "THIS IS X: {}".format(x)

    if x == "True":  
        x = "True"
    elif x == "False":
        x = "False"
    else:
        print 'invalid input!'
        x = 0 # very difficult but this works now!

print x

y = 0

while y == 0:
    y = str(raw_input("Please enter True or False again..."))
    y = y[0].upper()+ y[1:]

    if y == "True":
        y = "True"
    elif y == "False":
        y = "False"
    else:
        print 'invalid input!'
        y = 0

problem = 0
while problem == 0:
    problem = input("Please enter number: \n1 for AND, 2 for OR, 3 for NAND, 4 for NOR...")
    if problem == 1:
        print "I'm thinking.."
        time.sleep(2.5) 
        print "the answer is..."
        time.sleep(1.0) 
        print x, "AND", y, "is", x and y 

    elif problem == 2:
        print "I'm thinking.."
        time.sleep(2.5)
        print "the answer is..."
        time.sleep(1)
        print x, "OR", y, "is", x or y

    elif problem == 3:
        print "I'm thinking.."
        time.sleep(2.5)
        print "the answer is..."
        time.sleep(1)
        print x, "NAND", y, "is", not(x and y) # not working for false/false or false/true

    elif problem == 4:
        print "I'm thinking.."
        time.sleep(2.5)
        print "the answer is..."
        time.sleep(0.5)
        print x, "NOR", y, "is", not(x or y) # not working for false/false
    else:
        print 'invalid input'
        problem = 0

Answer 3

其他海报说得对 - Python认为0和False是相同的，至少是真实的。当然，我们人类知道它们不是类型相同的东西，你可以强制Python通过使用“is”而不是“==”来区分它，所以这条线应该变成......

while y is 0: # <-- change that line there
    y = str(raw_input("Please enter True or False again..."))
    y = y[0].upper()+ y[1:]

这是一个“严格比较”，比较值（Python认为是相同的）和类型（False是布尔值，0是数字）

Python简单项目不太合适

3 个答案: