Question

我正在寻找我认为是一项简单任务的帮助。：（

我在SQL Server实例中有一个包含以下列和数据的表：

num1   num2   num3   num4   num5
1      34     15     22     45
23     4      2      100    23
1      23     23     100    5

我希望获得计算所有数字出现的时间的结果：

Number  Count
1       2
2       2
3       0
4       1
5       1
6       0

Answer 1

对所需结果和SQL Server版本做出一些假设

SELECT Number,
       COUNT(*) AS [Count]
FROM   YourTable
CROSS APPLY (VALUES(num1),(num2),(num3),(num4),(num5)) V(Number)
GROUP BY Number

Answer 2

您可以使用UNPIVOT语句将所有值放入一列。然后是一个简单的GROUP BY和COUNT

select value, count(*)
from nums
unpivot
(
  value
  for col in (num1, num2, num3, num4, num5)
) u
group by value

SQL Fiddle

Answer 3

上述评论示例：

SELECT Number, COUNT(*) AS Count FROM (
SELECT num1 AS Number FROM MyTable
UNION ALL 
SELECT num2 AS Number FROM MyTable
UNION ALL 
SELECT num3 AS Number FROM MyTable
UNION ALL 
SELECT num4 AS Number FROM MyTable
UNION ALL 
SELECT num5 AS Number FROM MyTable
) t
GROUP BY Number

SQL Server：跨列的计数

3 个答案: