程序目标是将十进制转换为十六进制 1)我在向char数组元素分配整数值时遇到问题。如何完成。我得到我的数组数值的符号。 2)如何将数组初始化为空格?摆脱数组元素中的垃圾和旧数据。 3)有人可以解释我的问题是什么吗?整数和字符? 4)cout是我问题的一部分吗?
#include "stdafx.h"
#include <iostream>
#include <iomanip>
#include <math.h>
int main()
{
using namespace std;
// binary declarations
int x, i, z, n, remainder;
int result = 0;
bool loop_cond, remainder_found, octval_found;
// octal declarations
int octalval,octresult,octremainder,temp_octalval;
int octloop_cnt;
bool oct_loop;
octresult = 0;
// hexadecimal declarations
int hexval, hexremainder, temp_hexval;
int hexloop_cnt;
bool hex_loop,hexval_found;
char hexresult[5] = {" "};
cout << "decimal" << "\t" << "binary" << "\t"<< "octal"<<"\t"<<"hexadecimal"<< endl;
for (i = 1; i <= 256; i++){
hexloop_cnt = 0;
octremainder = 0;
hexval_found = false;
hex_loop = true;
hexloop_cnt = 0;
while (hex_loop != false){
if (hexval_found != true){
hexval = i / 16;
hexremainder = i % 16;
}
else {
temp_hexval = hexval;
hexval = hexval / 16;
hexremainder = temp_hexval % 16;
}
if (hexval == 0){
switch (hexremainder){
case 10:
hexresult[hexloop_cnt] = 'A';
break;
case 11:
hexresult[hexloop_cnt] = 'B';
break;
case 12:
hexresult[hexloop_cnt] = 'C';
break;
case 13:
hexresult[hexloop_cnt] = 'D';
break;
case 14:
hexresult[hexloop_cnt] = 'E';
break;
case 15:
hexresult[hexloop_cnt] = 'F';
break;
default:
hexresult[hexloop_cnt] = (char)hexremainder;
break;
}//end switch
hex_loop = false;
}//end if
if ((hexval < 16) && (hexval > 0)){
switch (hexremainder){
case 10:
hexresult[hexloop_cnt] = 'A';
break;
case 11:
hexresult[hexloop_cnt] = 'B';
break;
case 12:
hexresult[hexloop_cnt] = 'C';
break;
case 13:
hexresult[hexloop_cnt] = 'D';
break;
case 14:
hexresult[hexloop_cnt] = 'E';
break;
case 15:
hexresult[hexloop_cnt] = 'F';
break;
default:
hexresult[hexloop_cnt] = static_cast<char>(hexremainder);
break;
}//end switch
hexloop_cnt++;
switch (hexval){
case 10:
hexresult[hexloop_cnt] = 'A';
break;
case 11:
hexresult[hexloop_cnt] = 'B';
break;
case 12:
hexresult[hexloop_cnt] = 'C';
break;
case 13:
hexresult[hexloop_cnt] = 'D';
break;
case 14:
hexresult[hexloop_cnt] = 'E';
break;
case 15:
hexresult[hexloop_cnt] = 'F';
break;
default:
hexresult[hexloop_cnt] = static_cast<char>(hexval);
break;
}//end switch
hex_loop = false;
} //end if
if ((hexval >= 16)){
switch (hexremainder){
case 10:
hexresult[hexloop_cnt] = 'A';
break;
case 11:
hexresult[hexloop_cnt] = 'B';
break;
case 12:
hexresult[hexloop_cnt] = 'C';
break;
case 13:
hexresult[hexloop_cnt] = 'D';
break;
case 14:
hexresult[hexloop_cnt] = 'E';
break;
case 15:
hexresult[hexloop_cnt] = 'F';
break;
default:
hexresult[hexloop_cnt] = static_cast<char>(hexremainder);
break;
}//end switch
hexval_found = true;
}//end if
hexloop_cnt++;
} //endwhile
cout << i << "\t" << result <<"\t" << octresult<<"\t" << hexresult<< endl;
result = 0;
octresult = 0;
// hexresult[5] = { ' ', ' ', ' ', ' ', ' ' };
}
cin.clear();
cin.ignore(255, '/n');
cin.get();
return 0;
}
答案 0 :(得分:1)
你不能这样做
hexresult[hexloop_cnt] = (char)hexremainder;
你需要做
hexresult[hexloop_cnt] = hexremainder + '0';
为什么呢?好吧想想hexremainder = 1.字符的ascii&#34; 1&#34;不是0x01,它是0x31。所以你需要在值上加上0x30。 &#39; 0&#39;是0x30(查看ascii表以查看发生了什么http://www.asciitable.com/)
答案 1 :(得分:0)
std :: cout可能是问题所在。举个例子。
#include <iostream>
int main()
{
unsigned char c = 239;
std::cout << c << "\n";
std::cout << static_cast<int>(c) << "\n";
return 0;
}
输出:
./a.out
�
239