Question

有两个清单：

A：[[0, 1, 3, 4, 6, 7], [2, 5]]

B：[(0, 5), (0, 9), (1, 7), (5, 0), (5, 9), (7, 1), (9, 0), (9, 5)]

A中的数字0, 1, 2, 3, 4, 5, 6, 7对应

B中的

(0, 5), (0, 9), (1, 7), (5, 0), (5, 9), (7, 1), (9, 0), (9, 5)

是否有获取以下内容的快捷方式：

[[(0, 5), (0, 9), (5, 0), (5, 9), (9, 0), (9, 5)], [(1, 7),(7, 1)]]代表A？

Answer 1

使用operator.itemgetter和列表理解，就像这样

>>> indexes = [[0, 1, 3, 4, 6, 7], [2, 5]]
>>> data = [(0, 5), (0, 9), (1, 7), (5, 0), (5, 9), (7, 1), (9, 0), (9, 5)]
>>> from operator import itemgetter
>>> [list(itemgetter(*item)(data)) for item in indexes]
[[(0, 5), (0, 9), (5, 0), (5, 9), (9, 0), (9, 5)], [(1, 7), (7, 1)]]

相反，你可以使用嵌套列表理解，就像这样

>>> [[data[index] for index in items] for items in indexes]
[[(0, 5), (0, 9), (5, 0), (5, 9), (9, 0), (9, 5)], [(1, 7), (7, 1)]]

Answer 2

您可以简单地使用列表理解：

>>> A=[[0, 1, 3, 4, 6, 7], [2, 5]]
>>> B=[(0, 5), (0, 9), (1, 7), (5, 0), (5, 9), (7, 1), (9, 0), (9, 5)]
>>> C=[[B[i] for i in l] for l in A]
>>> C
[[(0, 5), (0, 9), (5, 0), (5, 9), (9, 0), (9, 5)], [(1, 7), (7, 1)]]

Answer 3

是的，快捷方式是：

[[B[j] for j in i] for i in A]

两个列表之间的交互

3 个答案: