Question

我使用Jersey javax.ws.rs来调用url

的java：

...
String eoEndPoint = "http://exemple.com/";
String url = "offres/test/2015-01-07?return=2015-01-09&withThac=false";
ClientConfig clientConfig = new ClientConfig();
Client client = ClientBuilder.newClient(clientConfig).register(new Authenticator(user, password));
WebTarget webTarget;
webTarget = client.target(eoEndPoint)
  .path(url);
Invocation.Builder invocationBuider = webTarget.request();
invocationBuider.accept(mediaType);
Offers response = invocationBuider.get(Offers.class);
return response;
...

当我执行此代码时，我有一个HTTP 404 Not Found 为什么invocationBuider.get(Offers.class);将我的网址http://exemple.com/offres/test/2015-01-07?return=2015-01-09&withThac=false转换为http://exemple.com/offres/test/2015-01-07%3Dreturn=2015-01-09&withThac=false

?转换为%3D为什么。？

Answer 1

您正在将查询参数传递给需要URI的path()方法，因此任何特殊字符（例如?，=）都会被转义。您需要使用专用方法queryParam()来提供查询参数。

替换

.path(url); // "offres/test/2015-01-07?return=2015-01-09&withThac=false";

与

.path("offres/test/2015-01-07")
.queryParam("return", "2015-01-09")
.queryParam("withThac", "false")

Jersey URL无效加密

1 个答案: