Question

#include <stdio.h>
#include <string.h>
main()
{
    char *a[]={"FrIiends is an american television sitcom",    //*line to be checked*
                "created by David crane and marta kauffman",
                "which originally aired on NBC"};
    int i=0,len=0,j=0,count=0;                            //Initialization of certain variables
    for(i=0;i<3;i++){
        count=0;                    //Count always made 0 for new line
        len=strlen(*(a+i));         //Lenght for new line is stored here every time
        for(j=0;j<len;j++){           
                if((int)*(*(a+i)+j)==97 || (int)*(*(a+i)+j)==101 || (int)*(*(a+i)+j)==105 || (int)*(*(a+i)+j)==111 || (int)*(*(a+i)+j)==117) //checking for vowels in lowercase
                    count=count +1;
                if ((int)*(*(a+i)+j)==65 || (int)*(*(a+i)+j)==69 || (int)*(*(a+i)+j)==73 || (int)*(*(a+i)+j)==79 || (int)*(*(a+i)+j)==85) //checking for vowels in Uppercase
                    count=count+1;
        }
         printf("Vowels in line %d are:%d\n",i+1,count);  //Final print statement


    }

}

以下代码可以正常工作，但是有另一种方法可以在以下指向数组的指针中计算元音吗？它的使用效率似乎也相当低。在上面我的案例中，我为大小写做了大量的测试用例。有没有办法忽略大小写或类似的东西。

Answer 1

#include <stdio.h>
#include <ctype.h>

int main(void){
    char *a[]={"FrIiends is an american television sitcom",
                "created by David crane and marta kauffman",
                "which originally aired on NBC"};
    char *p, ch;
    int i, count;
    for(i=0; i<3; ++i){
        count=0;
        p = *(a + i);//a[i];
        while(ch=tolower(*p++)){
            if(ch=='e' || ch=='a' || ch=='i' || ch=='o' || ch=='u')
                ++count;
        }
        printf("Vowels in line %d are:%d\n", i+1, count);
    }
    return 0;
}

检查以下字符串指针数组中的元音？

1 个答案: