我有3个表要加入以获取table1.code,table1.series,table2.entry_date,table3.title1 我正在尝试获取由table1.code和table1.series分组的最新非null table3.title1。
select table1.code, table1.series, max(table2.entry_date), table3.Title1
from table3 INNER JOIN table2 ON table3.ID = table2.ID
INNER JOIN table1 ON table2.source_code = table1.code
where table3.Title1 is not NULL
group by table1.code, table1.series, table3.Title1
似乎给了我所有带有非null title1的条目而不是最近的条目。我应该如何构建查询以便为每个代码选择最新版本的Title1&系列?
答案 0 :(得分:2)
试试这个:
select table1.code, table1.series, max(table2.entry_date), max(table3.Title1) as Title1
from table3
INNER JOIN table2 ON table3.ID = table2.ID
INNER JOIN table1 ON table2.source_code = table1.code
where table3.Title1 is not NULL
And Table2.entry_Date = (Select Max(sq.entry_Date)
From sq.table2
Where sq.id = table2.ID)
group by table1.code, table1.series
答案 1 :(得分:0)
也许像这样只能加入最新的table2条目?
SELECT
table1.code,
table1.series,
table2.entry_date,
table3.Title1
FROM
table1
INNER JOIN
table2
ON
table2.source_code = table1.code
AND
table2.entry_date =
(
SELECT
MAX(maxtable2.entry_date)
FROM
table2 maxtable2
WHERE
maxtable2.source_code = table2.source_code
)
INNER JOIN
table3
ON
table3.ID = table2.ID
答案 2 :(得分:0)
;with tlb as
(
select table1.code, table1.series, table2.entry_date, table3.Title1,
row_number() over(code, series, entry_date order by code, series, entry_date desc) as rn
from table3 INNER JOIN table2 ON table3.ID = table2.ID
INNER JOIN table1 ON table2.source_code = table1.code
where table3.Title1 is not NULL
)
select * from tlb where rn = 1
这可以非常快,具体取决于您的索引。