我新学习了node.js,我想使用json2csv节点模块将JSON对象解析为CSV文件。 json2csv仅支持平面结构,其中字段是json根的直接子节点。我找到了how-to-parse-json-object-to-csv-file-using-json2csv-nodejs-module主题并更改了json2csv的createColumnContent函数来读取我的json文件的对象elemet。 但我的json文件有数组元素,如下所示:
[
{
"firstName": "John",
"lastName": "Smith",
"age": 25,
"address": {
"streetAddress": "21 2nd Street",
"city": "New York",
"state": "NY",
"postalCode": "10021"
},
"phoneNumber": [
{
"type": "home",
"number": "212 555-1234"
},
{
"type": "fax",
"number": "646 555-4567"
}
]
},
{
"firstName": "John",
"lastName": "Smith",
"age": 25,
"address": {
"streetAddress": "21 2nd Street",
"city": "New York",
"state": "NY",
"postalCode": "10021"
},
"phoneNumber": [
{
"type": "home",
"number": "212 555-1234"
},
{
"type": "fax",
"number": "646 555-4567"
}
]
}
我想要那样的东西
我这样叫json2csv:
json2csv({
data: body.issues,
fields: ['firstName','lastname','age','address.city', 'phoneNumber[?].type', 'phoneNumber[?].number']
},
function(err, csv) {
if (err) console.log(err);
fs.writeFile('sample.csv', csv, function(err) {
if (err) throw err;
console.log('file saved');
});
}
);
如何读取数组并添加到我的csv文件中。 谢谢
答案 0 :(得分:5)
我刚刚发布了一个模块,可以在Node.js中轻松完成此过程
var jsonexport = require('jsonexport');
var contacts = [{
name: 'Bob',
lastname: 'Smith',
family: {
name: 'Peter',
type: 'Father'
}
},{
name: 'James',
lastname: 'David',
family:{
name: 'Julie',
type: 'Mother'
}
},{
name: 'Robert',
lastname: 'Miller',
family: null,
location: [1231,3214,4214]
},{
name: 'David',
lastname: 'Martin',
nickname: 'dmartin'
}];
jsonexport(contacts,function(err, csv){
if(err) return console.log(err);
console.log(csv);
});
输出:
lastname;name;family.type;family.name;nickname;location
Smith;Bob;Father;Peter;;
David;James;Mother;Julie;;
Miller;Robert;;;;1231,3214,4214
Martin;David;;;dmartin;
答案 1 :(得分:2)
你可能最好自己转换数据,而不是覆盖json2csv包的一部分。然后,您可以将平面数据结构传递给json2csv进行格式化。
var xform = [];
for (var i=0, max=data.issuelinks.length; i<max; i++ ) {
xform[xform.length] = { id:data.id, progress:data.progress.percent, issuelinkid:data.issuelinks[i].id, issuelinktypeid:data.issuelinks[i].type.id }
}
console.log(xform);