Question

我只是尝试使用一个字段＆＃34;用户名＆＃34;来验证表单（没有附加实体）。我想检查用户名是否存在。如果没有必要在表单错误级别显示正确的消息（或表单字段错误级别，我不在乎那么多）。

以下是我的控制器的相关部分：

$formGlobalSearch=$this->createFormBuilder()
->add('username', 'text', array('constraints' => new UsernameExists()))
->add('role', 'choice', array('choices' => $rolesListForForm,'required' => false, 'placeholder' => 'Choose a role', 'label' => false, ))
->add('submitUsername', 'submit', array('label' => 'Search username globally'))
->getForm();

$formGlobalSearch->handleRequest($request);

if ($formGlobalSearch->isValid())
    {
    // do something in the DB and refresh current page
    }

return $this->render(//all the stuff needed to render my page//);
}

以下是service.yml的相关部分

validator.unique.UsernameExists:
    class: AppBundle\Validator\Constraints\UsernameExists
    tags:
        - { name: validator.constraint_validator, alias: UsernameExists }

这是验证器类：

使用Symfony \ Component \ Validator \ Constraint;

/**
 * @Annotation
 */
class UsernameExists extends Constraint
{
public $message = 'The username "%string%" does not exist.';

public function validatedBy()
{
    return 'UsernameExists';
}
}

这是验证器：

<?php
namespace AppBundle\Validator\Constraints;

use Symfony\Component\Validator\Constraint;
use Symfony\Component\Validator\ConstraintValidator;

class UsernameExistsValidator extends ConstraintValidator
{
public function validate($value)
    {
    $globalUserToAdd = $this->getDoctrine()->getRepository('AppBundle:User')->findOneBy(
        array('username' => $value, 'enabled' => true)
        );

    if ($globalUserToAdd == null) //I did not find the user
        {
        $this->context->buildViolation($constraint->message)
            ->setParameter('%string%', $value)
            ->addViolation();
        }
    }
}

类和验证器位于目录＆＃34; AppBundle \ Validator \ Constraints＆＃34;

我收到以下错误：

预期的类型参数＆＃34; Symfony的\元器件\验证\ ConstraintValidatorInterface＆＃34 ;, ＆＃34;的appbundle \验证\约束\ UsernameExists＆＃34;给定

我当然在我的控制器上面有以下内容：

use AppBundle\Validator\Constraints\UsernameExists;

如果我将以下内容添加到service.yml

arguments: ["string"]

我收到错误：

没有为约束配置默认选项的appbundle \验证\约束\ UsernameExists

Answer 1

尝试改变：

public function validatedBy()
{
    return 'UsernameExists';
}

validator.unique.UsernameExists:
    class: AppBundle\Validator\Constraints\UsernameExists

为：

public function validatedBy()
{
    return 'UsernameExistsValidator';
}

validator.unique.UsernameExists:
    class: AppBundle\Validator\Constraints\UsernameExistsValidator

Answer 2

在这里合并（部分）建议和调试是最终的代码。

验证

<?php
namespace AppBundle\Validator\Constraints;

use Symfony\Component\Validator\Constraint;
use Symfony\Component\Validator\ConstraintValidator;
use Doctrine\ORM\EntityManager;

class UsernameExistsValidator extends ConstraintValidator
{

public function __construct(EntityManager $em) //added
{
    $this->em = $em;
}

public function validate($value, Constraint $constraint)
    {
    $em = $this->em;
    $globalUserToAdd = $em->getRepository('AppBundle:User')->findOneBy(
        array('username' => $value, 'enabled' => true)
        );

    if ($globalUserToAdd == null) //I did not find the user
        {
        $this->context->buildViolation($constraint->message)
            ->setParameter('%string%', $value)
            ->addViolation();
        }
    }
}

service.yml

validator.unique.UsernameExists:
    class: AppBundle\Validator\Constraints\UsernameExistsValidator
    arguments: [ @doctrine.orm.entity_manager, "string"]
    tags:
        - { name: validator.constraint_validator, alias: UsernameExists }

Symfony2自定义验证与数据库连接但没有实体

2 个答案: