Question

我有这个查询，我认为foreach有点错误....

public function lastsixcars(){
    // this function checks whether the user name exists and if its a match
    $result = $this->db->prepare("SELECT carID FROM AutoMarket_Selling ORDER BY carID DESC LIMIT 6");
    $result->execute();

    foreach($result as $result){
       echo $car = $result['ID'];
    }
}

我在页面上有这些......

<a href="details.php?carID=<?php echo $car ?>">
<a href="details.php?carID=<?php echo $car ?>">
<a href="details.php?carID=<?php echo $car ?>">
<a href="details.php?carID=<?php echo $car ?>">
<a href="details.php?carID=<?php echo $car ?>">
<a href="details.php?carID=<?php echo $car ?>">

...我希望数据库中的最后6个ID按顺序排列

因此...

<a href="details.php?carID=1st ID"> 
<a href="details.php?carID=2nd ID">
<a href="details.php?carID=3rd ID">
<a href="details.php?carID=4th ID">
<a href="details.php?carID=5th ID">
<a href="details.php?carID=6th ID">

任何人都可以告诉我如何做到这一点

感谢

Answer 1

使这个功能

function lastsixcars(){
    // this function checks whether the user name exists and if its a match
    $result = $this->db->prepare("SELECT carID FROM AutoMarket_Selling ORDER BY carID DESC LIMIT 6");
    $result->execute();

    foreach($result as $results){
       $return .= '<a href="details.php?carID='.$results['carID'].'">car '.$results['carID'].'</a>';
    }

   return $return;
}

这是php部分

echo lastsixcars();

Answer 2

使用

   echo $car = $result['carID'];

简而言之

foreach($result as $result){
        echo "<a href='details.php?carID=".$result['carID']."'>Car".$result['carID']."</a>";
}

Answer 3

对于foreach部分，这应该有效：

$results = array_slice($result, count($result) - 6);/* get the last 6 in the same order they are in the database*/

foreach ($results as $car) {
    echo '<a href="details.php?carID='.$car['0'].'">'; //assuming ID is the first field returned
}

希望它有所帮助。

从数据库PHP PDO中回收最后6个ID

3 个答案: