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Question

通过此命令php codecept.phar run api LoginCest.php --steps运行测试项目后，我得到以下输出：

* am trying  to login.........
* I have http header "Content-Type","application/x-www-form-urlencoded"
* I send post "?",{"operation":"login","username":"xyz@abc.com","accessKey":"xyz"}
* I grab data from json response 
* see test status:Passed.

但我只得到这个输出：

 * am trying  to login.........
 * see test status:Passed.

这是我的代码：

    $I->comment(" am trying  to login.........");
    $postData = array(
        'operation' => 'login',
        'username' => $username,
        'accessKey' => $password
    );
    $url = "?";
    $I->haveHttpHeader('Content-Type', 'application/x-www-form-urlencoded');
    $I->sendPOST($url, $postData);
    $outputData = $I->grabDataFromJsonResponse();

    if ($outputData['success'] == true) {
        $I->comment("see test status:Passed.");
    } else {
        $I->comment("see test status:Failed.");
    }

只获取此方法输出：

 $I->comment();

Answer 1

使用选项-d

在调试模式下运行代码

php codecept.phar run -d