鉴于父/子关系的集合,我如何构建嵌套地图以显示此结构?
例如,我该如何转换这些数据:
({"child" "1.1",
"parent" "1"}
{"child" "1.2",
"parent" "1"}
{"child" "1.3",
"parent" "1"}
{"child" "1.4",
"parent" "1"}
{"child" "1.1.1",
"parent" "1.1"}
{"child" "1.1.2",
"parent" "1.1"}
{"child" "2.1",
"parent" "2"}
{"child" "2.2",
"parent" "2"}
{"child" "2.3",
"parent" "2"})
进入这个:
{"1" {"1.1" {"1.1.1" {}
"1.1.2" {}}
"1.2" {}
"1.3" {}
"1.4" {}}
"2" {"2.1" {}
"2.2" {}
"2.3" {}}}
我正在使用的实际数据是:
({"child" "94bf72cb-01cd-4430-b669-b2e954b5639b",
"parent" "6378daf6-3b7f-4cf4-8156-a50cf5f7b6ef"}
{"child" "8c9c57a0-d20d-4474-9afb-c9d17df83a91",
"parent" "6378daf6-3b7f-4cf4-8156-a50cf5f7b6ef"}
{"child" "73d2a203-e3c1-4d2f-aaf8-a9f2e870792b",
"parent" "6378daf6-3b7f-4cf4-8156-a50cf5f7b6ef"}
{"child" "669fe949-057f-43c0-af7b-ff39594a183d",
"parent" "6378daf6-3b7f-4cf4-8156-a50cf5f7b6ef"}
{"child" "1ceff8fe-a0a8-46ad-81a8-d13fb837aaf6",
"parent" "94bf72cb-01cd-4430-b669-b2e954b5639b"}
{"child" "ba96a425-a3f0-4ce5-8c19-6ea9add14013",
"parent" "94bf72cb-01cd-4430-b669-b2e954b5639b"}
{"child" "160f34ac-68b9-4c8e-930b-1ab6df895df4",
"parent" "1ce9b863-5681-4660-85e7-fbd0cc184aed"}
{"child" "58825b50-23bc-4204-8f8d-c9a9d3ac8beb",
"parent" "1ce9b863-5681-4660-85e7-fbd0cc184aed"}
{"child" "4b1763f9-8380-4507-9a8f-5c86878e49a9",
"parent" "1ce9b863-5681-4660-85e7-fbd0cc184aed"})
答案 0 :(得分:2)
您可以将子父关系转换为邻接列表,然后遍历非循环有向图以创建嵌套映射。
(defn adjacency-list [coll]
(reduce (fn [r {p "parent" c "child"}]
(-> r
(update-in [:counts p] #(or % 0))
(update-in [:counts c] #(if % (inc %) 1))
(update-in [:adjacency p] #(if % (conj % c) [c]))))
{}
coll))
(defn root-nodes [counts]
(mapv key
(filter (comp zero? val) counts)))
(defn traverse [m al roots]
(reduce (fn [r k]
(assoc r k
(if-let [v (get al k)]
(traverse {} al v)
{})))
m
roots))
(def data '({"child" "1.1", "parent" "1"} {"child" "1.2", "parent" "1"} {"child" "1.3", "parent" "1"} {"child" "1.4", "parent" "1"} {"child" "1.1.1", "parent" "1.1"} {"child" "1.1.2", "parent" "1.1"} {"child" "2.1", "parent" "2"} {"child" "2.2", "parent" "2"} {"child" "2.3", "parent" "2"}))
(let [{:keys [counts adjacency]} (adjacency-list data)]
(clojure.pprint/pprint (traverse {} adjacency (root-nodes counts))))
;=> {"2" {"2.3" {}, "2.2" {}, "2.1" {}},
; "1" {"1.4" {}, "1.3" {}, "1.2" {}, "1.1" {"1.1.2" {}, "1.1.1" {}}}}