功能指针带＆amp;没有

Question

有什么区别：

int (*wskNaF)(int, int) = addition;

和这一行

int (*wskNaF)(int, int) = &addition;

分数完全相同：

#include <cstdio>

int addition( int a, int b );

int (*wskNaF)(int, int) = addition;
//int (*wskNaF)(int, int) = &addition;

int main()
{
  printf("Score= %d\n", wskNaF(5,7));
  return 0;
}

int addition( int a, int b )
{
  return a + b;
}
// g++ test.cpp -o test && ./test

我认为函数名也是她的指针？我错了吗？