我有一个由performSegueWithIdentifier:
逐步调用的segue但它不会触发。但是,当我用按钮创建segue按segue工作没有问题。我也尝试在代码中更改我的segue的名称,并产生no segue with identifier
错误。
这是我的代码(注意:在两个不同的地方调用segue以检查它是否可以在代码中的其他位置工作。)
#import "SignUpViewController.h"
#import "ProgressHUD.h"
@interface SignUpViewController ()
@end
@implementation SignUpViewController
- (void)viewDidLoad {
[super viewDidLoad];
// Do any additional setup after loading the view.
[self performSegueWithIdentifier:@"profilePic" sender:self];
}
- (void)didReceiveMemoryWarning {
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}
/*
#pragma mark - Navigation
// In a storyboard-based application, you will often want to do a little preparation before navigation
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
// Get the new view controller using [segue destinationViewController].
// Pass the selected object to the new view controller.
}
*/
- (IBAction)createAnAccount:(id)sender {
[ProgressHUD show:@"Please Wait"];
if ([self.passwrod.text isEqualToString:self.confirmPassword.text]){
// Register User
PFUser *user = [PFUser user];
user.username = self.username.text;
user.password = self.passwrod.text;
user.email = self.eMail.text;
// other fields can be set if you want to save more information
NSString *name = [self.firstName.text stringByAppendingString:@" "];
NSString *fullName = [name stringByAppendingString:self.lastName.text];
user[@"name"] = fullName;
user[@"posts"] = @0;
user[@"score"] = @5;
user[@"followers"] = @0;
user[@"following"] = @0;
[user signUpInBackgroundWithBlock:^(BOOL succeeded, NSError *error) {
if (!error) {
// Hooray! Let them use the app now.
[self performSegueWithIdentifier:@"profilePic" sender:self];
[ProgressHUD showSuccess:nil];
NSLog(@"Perform Segue");
} else {
NSString *errorString = [error userInfo][@"error"];
// Show the errorString somewhere and let the user try again.
[ProgressHUD showError:errorString];
}
}];
} else {
// Alert User
[ProgressHUD showError:@"Please check your passwords as they do not match."];
}
}
-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
NSLog(@"Preparing for segue");
NSLog(@"Segue: %@", segue.identifier);
}
@end
更新澄清:正在调用prepareForSegue
方法并记录。
感谢您的帮助!
答案 0 :(得分:4)
您不应该在performSegueWithIdentifier
中致电viewDidLoad
。事实上,如果你这样做,我很确定你会在控制台中看到警告或错误。将呼叫转移到viewDidAppear
。
答案 1 :(得分:0)
对我有用的解决方案是删除所讨论的视图控制器的所有segue,然后重新添加它们。这可能对每个人都不起作用,但值得一试。