Question

我想知道如何使用php询问时间是否大于

08:30

且低于

21:15

如果我使用：

<?php

if ( (date("H")>8&&date("i")>30) && (date("H")<21&&date("i")<25) ) {
echo 'This website is closed from 08:30 - 21:25. Sorry for the Inconvenience.';
exit;

}

?>

这不是一个准确的说法，因为即使时间大于8且低于21，这里还有一分钟验证...

Answer 1

您可以获取日期部分的日期/时间和条带。该时间可以与其他时间值进行比较。在下面的代码中，我计算当前时间（8：30和21:15）午夜的秒数值，然后if变得非常简单：

define('SecondsPerDay', 86400);
define('SecondsPerHour', 3600);
define('SecondsPerMinute', 60);

$time = time () % SecondsPerDay;

$from = 8 * SecondsPerHour + 30 * SecondsPerMinute;
$to = 21 * SecondsPerHour + 15 * SecondsPerMinute;

if ($time >= $from && $time < $to) {
  echo 'This website is closed from 08:30 - 21:25. Sorry for the Inconvenience.';
  exit;
}

Answer 2

$startTime = '08:30';
$endTime = '21:15';
$time = new DateTime($startTime);
$time1 =  date_format($time, 'H:i'); 
$time = new DateTime($endTime);
$time2 =  date_format($time, 'H:i');
"Today is " . $current =date("H:i") . "<br>";
if ($current > $time1 && $current < $time2)
{
echo 'This website is closed from 08:30 - 21:25. Sorry for the Inconvenience.';
}else{

echo "It's open";
}

REFERENCE

如果时间大于和小于

2 个答案: