我正在编写一个Chrome扩展程序，它正在使用CryptoJS进行一些Apache Thrift工作。我目前正在尝试使CryptoJS正常工作。我遇到CryptoJS加密数据的CryptoJS解密问题。在问题描述之后，我在下面附上一个测试用例。
发生的事情如下，我有一个“字节”数组：
var bArr = [11,0,1,0,0,0,6,100,105,103,101,115,116,11,0,2,0,0,0,152,67,119,65,66,65,65,65,65,69,109,78,111,99,109,57,116,90,83,49,48,90,88,78,48,76,87,78,115,97,87,86,117,100,65,103,65,65,103,65,65,49,68,69,75,65,65,77,65,65,65,65,65,86,75,102,66,85,103,115,65,66,65,65,65,65,67,81,49,90,68,99,119,77,71,73,120,78,67,48,121,78,84,90,107,76,84,81,119,77,109,81,116,79,84,65,48,90,105,48,52,79,84,86,105,78,68,73,50,89,109,78,108,78,84,99,76,65,65,85,65,65,65,65,85,89,50,104,121,98,50,49,108,76,87,78,115,97,87,86,117,100,67,49,122,90,87,78,121,90,88,81,65,11,0,3,0,0,0,36,52,51,52,55,54,56,98,53,45,50,48,102,102,45,52,99,100,102,45,56,53,97,50,45,57,49,49,56,50,98,55,98,51,102,57,53,0];
var stringToEncode = String.fromCharCode.apply(null, bArr);
我使用CryptoJS对其进行加密，然后解密。加密前的前25个字节：
11,0,1,0,0,0,6,100,105,103,101,115,116,11,0,2,0,0,0,152,67,119,65,66,65
解密后：
11,0,1,0,0,0,6,100,105,103,101,115,116,11,0,2,0,0,0,194,152,67,119,65,66
唯一的区别是在位置20处增加了194.显然，除了填充之外，所有其他字节完全相同。我试图了解它的来源。
有关帽子的更多信息是这些字节。这是一个有3个字段的Thrift结构，字段2包含另一个嵌入式Thrift结构的Base64表示。输出的前20个字节：
由于解密问题，Thrift解析器错误地识别了fid 2值的长度。
我相信我在使用带有PKCS7填充的OpenSSL模式下使用带有32字节密钥（SHA256）和16字节IV的AES256 CBC。
这是我的qunit测试。
test("Decryption", function() {
var bArr = [11,0,1,0,0,0,6,100,105,103,101,115,116,11,0,2,0,0,0,152,67,119,65,66,65,65,65,65,69,109,78,111,99,109,57,116,90,83,49,48,90,88,78,48,76,87,78,115,97,87,86,117,100,65,103,65,65,103,65,65,49,68,69,75,65,65,77,65,65,65,65,65,86,75,102,66,85,103,115,65,66,65,65,65,65,67,81,49,90,68,99,119,77,71,73,120,78,67,48,121,78,84,90,107,76,84,81,119,77,109,81,116,79,84,65,48,90,105,48,52,79,84,86,105,78,68,73,50,89,109,78,108,78,84,99,76,65,65,85,65,65,65,65,85,89,50,104,121,98,50,49,108,76,87,78,115,97,87,86,117,100,67,49,122,90,87,78,121,90,88,81,65,11,0,3,0,0,0,36,52,51,52,55,54,56,98,53,45,50,48,102,102,45,52,99,100,102,45,56,53,97,50,45,57,49,49,56,50,98,55,98,51,102,57,53,0];
var stringToEncode = String.fromCharCode.apply(null, bArr);
var symmetricKey = "v3JElaRswYgxOt4b";
var key = CryptoJS.enc.Latin1.parse( CryptoJS.enc.Latin1.stringify( CryptoJS.SHA256( symmetricKey ) ) );
var iv = CryptoJS.lib.WordArray.random( 16 );
var encrypted = CryptoJS.AES.encrypt( stringToEncode,
key,
{ iv: iv, format: CryptoJS.format.OpenSSL }
).ciphertext.toString(CryptoJS.enc.Latin1);
var decrypted = CryptoJS.AES.decrypt( { ciphertext: CryptoJS.enc.Latin1.parse(encrypted) },
key,
{ iv: iv, padding: CryptoJS.pad.NoPadding }
).toString(CryptoJS.enc.Latin1);
var buf = [];
for (var i=0; i<decrypted.length; i++) {
buf.push( decrypted.charCodeAt(i) );
}
var bstr1 = "";
for (var i=0; i<bArr.length; i++) {
bstr1 += (i>0) ? ","+bArr[i] : bArr[i]+"";
}
var bstr2 = "";
for (var i=0; i<buf.length; i++) {
bstr2 += (i>0) ? ","+buf[i] : buf[i]+"";
}
console.log("------------------------------------------");
console.log(bstr1);
console.log(bstr2);
console.log("------------------------------------------");
equal( stringToEncode.slice(0,200), decrypted.slice(0,200) );
});
我的测试HTML包装器加载了这些：
<script src="../bower_components/jquery/dist/jquery.min.js"></script>
<script src="../bower_components/js-base64/base64.js"></script>
<script src="../bower_components/thrift/lib/js/src/thrift.js"></script>
<script src="../bower_components/underscore/underscore-min.js"></script>
<script src="../bower_components/qunit/qunit/qunit.js"></script>
<script src="../bower_components/browserify-cryptojs/components/core.js"></script>
<script src="../bower_components/browserify-cryptojs/components/sha256.js"></script>
<script src="../bower_components/browserify-cryptojs/components/enc-base64.js"></script>
<script src="../bower_components/browserify-cryptojs/components/cipher-core.js"></script>
<script src="../bower_components/browserify-cryptojs/components/format-hex.js"></script>
<script src="../bower_components/browserify-cryptojs/components/aes.js"></script>
<script src="../bower_components/browserify-cryptojs/components/pad-nopadding.js"></script>
<!-- the Test Suite-->
<script type="text/javascript" src="test-client.js" charset="utf-8"></script>
<!-- CSS-->
<link rel="stylesheet" href="../bower_components/qunit/qunit/qunit.css" type="text/css" media="screen" />
我的bower.json是：
{
"name": "gossiperl-client-chrome",
"version": "0.1.0",
"main": "manifest.json",
"dependencies": {
"jquery": "~1.11.0",
"underscore": "~1.7.0",
"thrift": "radekg/thrift#js-binary-protocol",
"js-base64": "~2.1.5",
"qunit": "~1.14.0",
"browserify-cryptojs": "~0.3.1"
},
"authors": [
"radekg <...@....com>"
],
"description": "Gossiperl Chrome client with a sample application",
"keywords": [
"gossiperl",
"client"
],
"license": "MIT",
"homepage": "http://....com",
"private": true
}
答案 0 :(得分：1)
问题是CryptoJS将输入视为UTF-8输入字符串，除非它已经是WordArray。如果您的输入不是UTF-8，这当然是个问题。你看到的是，0x80（128）以上的值被转换为两个字节来修复UTF-8编码。
只要WordArray不支持从数组直接转换为WordArray，您就可以使用直接转换为十六进制，然后转换为WordArray。这个功能缺失有点奇怪。
以下将具有无符号字节值的数组转换为十六进制（对于无效字节值，使用一个保护位）：
function tohex(unsignedByteArray) {
var hex = "";
for (var i = 0; i < unsignedByteArray.length; i++) {
var c = unsignedByteArray[i];
if (c < 0 || c > 255) {
throw "Value not an unsigned byte in array";
}
var h = c.toString(16);
if (h.length == 1) {
hex += "0" + h;
} else {
hex += h;
}
}
return hex;
}
function fromhex(hex) {
if (hex.length % 2 !== 0) {
throw "Hex string should contain even number of hex digits, one per byte";
}
var unsignedByteArray = [];
for (var i = 0; i < hex.length; i = i + 2) {
var h = hex.substring(i, i + 2);
if (!/^[0-9a-f]{2}$/i.test(h)) {
throw "Invalid hexdigit at offset " + i;
}
var c = parseInt(h, 16);
unsignedByteArray[unsignedByteArray.length] = c;
}
return unsignedByteArray;
}
所以你可以使用这样的函数：
var bArr = [11, 0, 1, 0, 0, 0, 6, 100, 105, 103, 101, 115, 116, 11, 0, 2, 0, 0, 0, 152, 67, 119, 65, 66, 65, 65, 65, 65, 69, 109, 78, 111, 99, 109, 57, 116, 90, 83, 49, 48, 90, 88, 78, 48, 76, 87, 78, 115, 97, 87, 86, 117, 100, 65, 103, 65, 65, 103, 65, 65, 49, 68, 69, 75, 65, 65, 77, 65, 65, 65, 65, 65, 86, 75, 102, 66, 85, 103, 115, 65, 66, 65, 65, 65, 65, 67, 81, 49, 90, 68, 99, 119, 77, 71, 73, 120, 78, 67, 48, 121, 78, 84, 90, 107, 76, 84, 81, 119, 77, 109, 81, 116, 79, 84, 65, 48, 90, 105, 48, 52, 79, 84, 86, 105, 78, 68, 73, 50, 89, 109, 78, 108, 78, 84, 99, 76, 65, 65, 85, 65, 65, 65, 65, 85, 89, 50, 104, 121, 98, 50, 49, 108, 76, 87, 78, 115, 97, 87, 86, 117, 100, 67, 49, 122, 90, 87, 78, 121, 90, 88, 81, 65, 11, 0, 3, 0, 0, 0, 36, 52, 51, 52, 55, 54, 56, 98, 53, 45, 50, 48, 102, 102, 45, 52, 99, 100, 102, 45, 56, 53, 97, 50, 45, 57, 49, 49, 56, 50, 98, 55, 98, 51, 102, 57, 53, 0];
var bArrHex = tohex(bArr);
var stringToEncode = CryptoJS.enc.Hex.parse(bArrHex);
var symmetricKey = "v3JElaRswYgxOt4b";
var key = CryptoJS.enc.Latin1.parse(CryptoJS.enc.Latin1.stringify(CryptoJS.SHA256(symmetricKey)));
var iv = CryptoJS.lib.WordArray.random(16);
var encrypted = CryptoJS.AES.encrypt(stringToEncode, key, { iv: iv, format: CryptoJS.format.OpenSSL });
var decrypted = CryptoJS.AES.decrypt(encrypted, key, { iv: iv, format: CryptoJS.format.OpenSSL });
var result = fromhex(decrypted.toString(CryptoJS.enc.Hex));
console.log(result);
if (bArr.toString() == result.toString()) {
console.log("success");
}
请注意，encrypted在用作字符串时会自动编码为base64。您不能将Latin1编码用于密文。请注意，您的密钥还应包含随机字节，而不仅仅是现在可打印的字符。
最后请注意，在没有MAC的情况下发送AES加密文本本质上是不安全的，例如因为填充oracle攻击以及任何人都可以更改传输中的数据这一事实。
答案 1 :(得分：1)
仅作为补充参考。接受的答案包含问题的关键。
问题是CryptoJS将输入视为UTF-8输入字符串，除非它已经是WordArray。
的确，我已将测试改为以下内容：
test("Decryption", function() {
var bArr = [11,0,1,0,0,0,6,100,105,103,101,115,116,11,0,2,0,0,0,152,67,119,65,66,65,65,65,65,69,109,78,111,99,109,57,116,90,83,49,48,90,88,78,48,76,87,78,115,97,87,86,117,100,65,103,65,65,103,65,65,49,68,69,75,65,65,77,65,65,65,65,65,86,75,102,66,85,103,115,65,66,65,65,65,65,67,81,49,90,68,99,119,77,71,73,120,78,67,48,121,78,84,90,107,76,84,81,119,77,109,81,116,79,84,65,48,90,105,48,52,79,84,86,105,78,68,73,50,89,109,78,108,78,84,99,76,65,65,85,65,65,65,65,85,89,50,104,121,98,50,49,108,76,87,78,115,97,87,86,117,100,67,49,122,90,87,78,121,90,88,81,65,11,0,3,0,0,0,36,52,51,52,55,54,56,98,53,45,50,48,102,102,45,52,99,100,102,45,56,53,97,50,45,57,49,49,56,50,98,55,98,51,102,57,53,0];
var dataToEncrypt = toCryptoJSWordArray( bArr );
var symmetricKey = "v3JElaRswYgxOt4b";
var key = CryptoJS.enc.Latin1.parse( CryptoJS.enc.Latin1.stringify( CryptoJS.SHA256( symmetricKey ) ) );
var iv = CryptoJS.lib.WordArray.random( 16 );
var encrypted = CryptoJS.AES.encrypt( dataToEncrypt,
key,
{ iv: iv, format: CryptoJS.format.OpenSSL }
).ciphertext.toString(CryptoJS.enc.Latin1);
var decrypted = toByteArray( CryptoJS.AES.decrypt( { ciphertext: CryptoJS.enc.Latin1.parse(encrypted) },
key,
{ iv: iv, padding: CryptoJS.pad.NoPadding }
).toString(CryptoJS.enc.Latin1) );
var bstr1 = "";
for (var i=0; i<bArr.length; i++) {
bstr1 += (i>0) ? ","+bArr[i] : bArr[i]+"";
}
var bstr2 = "";
for (var i=0; i<decrypted.length; i++) {
bstr2 += (i>0) ? ","+decrypted[i] : decrypted[i]+"";
}
console.log("------------------------------------------");
console.log(bstr1);
console.log(bstr2);
console.log("------------------------------------------");
deepEqual( bArr.slice(0,200), decrypted.slice(0,200) );
});
function toCryptoJSWordArray(bArr) {
var latin1StrLength = bArr.length;
// Convert
var words = [];
for (var i = 0; i < bArr.length; i++) {
words[i >>> 2] |= (bArr[i] & 0xff) << (24 - (i % 4) * 8);
}
return new CryptoJS.lib.WordArray.init(words, bArr.length);
}
function toByteArray(str) {
var bArr = [];
for (var i=0; i<str.length; i++) {
bArr.push( str.charCodeAt(i) );
}
return bArr;
}
这将从我的bytearray创建一个WordArray，然后加密和解密。解密的数据正确返回。