我正在尝试上传在iOS上使用Cordova Media Plugin录制的音频文件。 音频文件已创建,我可以播放它们。
但是我找不到从文件系统上传录像的有效解决方案。我的录音代码是:
record = new Media(src,
// success callback
function () {
console.log("recordAudio():Audio Success");
},
// error callback
function (err) {
console.log("recordAudio():Audio Error: " + err.code);
});
// Record audio
record.startRecord();
//when finished
record.stopRecord();
答案 0 :(得分:14)
我发现了怎么做:
在iOS上,您必须首先添加Cordova文件系统插件以创建新条目。
cordova plugin add org.apache.cordova.file
创建记录文件并设置全局变量fileURL和audioRecord:
//Prepares File System for Audio Recording
audioRecord = 'record.wav';
onDeviceReady();
function onDeviceReady() {
window.requestFileSystem(LocalFileSystem.TEMPORARY, 0, gotFS, fail);
}
function gotFS(fileSystem) {
fileSystem.root.getFile(audioRecord, {
create: true,
exclusive: false
}, gotFileEntry, fail);
}
function gotFileEntry(fileEntry) {
fileURL = fileEntry.toURL();
}
开始和停止记录:
record = new Media(audioRecord,
// success callback
function () {
console.log("recordAudio():Audio Succes: ");
},
// error callback
function (err) {
console.log("recordAudio():Audio Error: " + err.code);
});
// Record audio
record.startRecord();
// Wait
record.stopRecord();
要上传文件,首先要添加文件传输插件:
cordova plugin add org.apache.cordova.file-transfer
然后您可以调用此方法上传记录:
//Method to upload Audio file to server
var uploadAudio = function () {
var win = function (r) {
console.log("Code = " + r.responseCode);
console.log("Response = " + r.response);
console.log("Sent = " + r.bytesSent);
}
var fail = function (error) {
alert("An error has occurred: Code = " + error.code);
console.log("upload error source " + error.source);
console.log("upload error target " + error.target);
}
var options = new FileUploadOptions();
options.fileKey = "file";
options.fileName = "recordupload.wav";
options.mimeType = "audio/wav";
var ft = new FileTransfer();
ft.upload(fileURL, encodeURI("http://yoururl.com/uploadaudio.php"), win, fail, options);
}
要接收文件,您可以使用此PHP脚本:
<?php
// Where the file is going to be placed
$target_path = "records/";
/* Add the original filename to our target path.
Result is "uploads/filename.extension" */
$target_path = $target_path . basename( $_FILES['file']['name']);
if(move_uploaded_file($_FILES['file']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['file']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
echo "filename: " . basename( $_FILES['file']['name']);
echo "target_path: " .$target_path;
}
?>
答案 1 :(得分:0)
使用FileTransfer插件https://github.com/apache/cordova-plugin-file-transfer/blob/master/doc/index.md。要安装do:
cordova plugin add https://git-wip-us.apache.org/repos/asf/cordova-plugin-file-transfer.git
然后这样做
var ft = new FileTransfer();
var success = function (r) {
// success code here
};
var fail = function (error) {
// failure code here
alert('File could not be uploaded');
};
options.fileKey = 'image'; // set the key for the server to know where the cotent is
options.fileName = '/myfile.jpg'; // location of your file
options.mimeType = "image/jpeg"; // mimeType
params.myParam = 'My Value'; // add other parameters if required
options.params = params;
ft.upload(fileURI, encodeURI('/path/to/my/post/handler'), success, fail, options);