Question

我正在尝试在 Movie 以外的类中初始化 Movie 类型的列表，而这两个类都位于同一名称空间中。代码在下面提到：

namespace MovieListCaseStudy
{
    class Movie
    {
        private int id;

        public int Id
        {
            get { return id; }
            set { id = value; }
        }
        private string name;

        public string Name
        {
            get { return name; }
            set { name = value; }
        }
        private float duration;

        public float Duration
        {
            get { return duration; }
            set { duration = value; }
        }
        private float price;

        public float Price
        {
            get { return price; }
            set { price = value; }
        }
    }
}

******

namespace MovieListCaseStudy
{
    class BusinessLogic
    {
        List<Movie> movielist = new List<Movie>();
        {
            {Id=1, Name="pk", Duration=2, Price=200}

        };
    }
}

问题是 BusinessLogic 类中未标识Id，Name等属性。请帮助。

Answer 1

您错过了new Movie()：

List<Movie> movielist = new List<Movie>()
{
    new Movie() { Id=1, Name="pk", Duration=2, Price=200 }
};

Answer 2

删除尾部半冒号，并根据@Marcin使用new Movie()构造。另请注意，默认构造函数parenths ()对于初始化程序是可选的：

class BusinessLogic
{
    List<Movie> movielist = new List<Movie>
    {
        new Movie {Id=1, Name="pk", Duration=2, Price=200}
    };
}

顺便说一下，Array初始化可以使用另一种速记，但在这种情况下需要额外的.ToList()转换，在这种情况下效率会降低：

class BusinessLogic
{
    List<Movie> movielist = new [] // No type needed, will be inferred
    {
        new Movie {Id=1, Name="pk", Duration=2, Price=200}
    }
    .ToList();
}

初始化列表时遇到问题

2 个答案: