Question

我正在尝试进行预处理，并希望将classe因子值{A,B,C,D,E}转换为{1,2,3,4,5}。

classe列的类型为factor，我提供了所有步骤，如下所示：

    #get the data
    training <- read.table("http://d396qusza40orc.cloudfront.net/predmachlearn/pml-training.csv",header=TRUE, sep=",", na.strings="NA", dec=".", strip.white=TRUE)
    training_df <- data.frame(training,stringsAsFactors=FALSE)

    #split to training & test sets
    inTrain <- createDataPartition(y=training$classe, p=0.75, list=FALSE)
    training_data <- training[inTrain,]
    testing_data <- training[-inTrain,]

    #subset based on columns of interest, based on previous studies
    training_data_subset <- subset(training_data, select=c("avg_roll_belt","var_roll_belt","var_total_accel_belt","amplitude_roll_belt","max_roll_belt","var_roll_belt",
    "var_accel_arm","magnet_arm_x","magnet_arm_y","magnet_arm_z","accel_dumbbell_y","accel_dumbbell_z","magnet_dumbbell_x","gyros_dumbbell_x",
    "gyros_dumbbell_y","gyros_dumbbell_z","pitch_forearm","gyros_forearm_x","gyros_forearm_y","classe"))

    #see which columns are factors, the training_data_subset#classe feature is a factor
    sapply(training_data_subset, class)

#sapply output

 avg_roll_belt        var_roll_belt var_total_accel_belt  amplitude_roll_belt        max_roll_belt 
           "numeric"            "numeric"            "numeric"            "numeric"            "numeric" 
     var_roll_belt.1        var_accel_arm         magnet_arm_x         magnet_arm_y         magnet_arm_z 
           "numeric"            "numeric"            "integer"            "integer"            "integer" 
    accel_dumbbell_y     accel_dumbbell_z    magnet_dumbbell_x     gyros_dumbbell_x     gyros_dumbbell_y 
           "integer"            "integer"            "integer"            "numeric"            "numeric" 
    gyros_dumbbell_z        pitch_forearm      gyros_forearm_x      gyros_forearm_y               classe 
           "numeric"            "numeric"            "numeric"            "numeric"             "factor"

我创建了一个试图替换A = 1，B = 2，C = 3，D = 4，E = 5的函数，见下文：

factorsToNumeric <- function(data)
{
    data_numeric <- data
    data_numeric$classe <-as.numeric(factor(toupper(as.character(data_numeric$classe))))
    #loop through the data frame based on replace values
    for(i in 1:nrow(data_numeric)) 
    {

    if ((data_numeric[i,]$classe == "A") || (data_numeric[i,]$classe  == "a")) 
    {data_numeric[i,]$classe <- "1"}
    else if ((data_numeric[i,]$classe  == "B") || (data_numeric[i,]$classe  == "b"))
    {data_numeric[i,]$classe <- "2"}
    else if ((data_numeric[i,]$classe  == "C") || (data_numeric[i,]$classe  == "c"))
    {data_numeric[i,]$classe <- "3"}
    else if ((data_numeric[i,]$classe  == "D") || (data_numeric[i,]$classe  == "d"))
    {data_numeric[i,]$classe <- "4"}
    else if ((data_numeric[i,]$classe  == "E") || (data_numeric[i,]$classe  == "e"))
    {data_numeric[i,]$classe <- "5"}
    else 
    {
    #do nothing 
    }

    }

    return (data_numeric)
}

然而，我收到此错误：

training_data_subset_numeric <- factorsToNumeric(training_data_subset)

错误：

Warning messages:
1: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
2: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
3: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
4: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
5: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
6: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
7: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
8: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
9: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated

进一步检查显示，该列＆＃34; classe＆＃34;的班级被转换为＆＃34;数字＆＃34;：

 sapply(training_data_subset_numeric, class)

 avg_roll_belt        var_roll_belt var_total_accel_belt  amplitude_roll_belt        max_roll_belt 
       "numeric"            "numeric"            "numeric"            "numeric"            "numeric" 
 var_roll_belt.1        var_accel_arm         magnet_arm_x         magnet_arm_y         magnet_arm_z 
       "numeric"            "numeric"            "integer"            "integer"            "integer" 
accel_dumbbell_y     accel_dumbbell_z    magnet_dumbbell_x     gyros_dumbbell_x     gyros_dumbbell_y 
       "integer"            "integer"            "integer"            "numeric"            "numeric" 
gyros_dumbbell_z        pitch_forearm      gyros_forearm_x      gyros_forearm_y               classe 
       "numeric"            "numeric"            "numeric"            "numeric"            "numeric"

然而，头部功能确认了上述错误＆amp;所有值A，B，C，D，E都被错误地替换为NA。

Answer 1

因素不起作用。您不能像其他数据类型那样使用简单的<-赋值更改值。您可以通过几种不同的方式更改因素。这是使用levels<-替换函数的一种方式。

以下是您的大量数据中的示例，这些数据花了太长时间才能阅读:)对于这些数据而言，这很简单，因为这些级别已经按正确的顺序排列。

set.seed(2)
x <- sample(training$classe, 20)
x
# [1] A D C A E E A E B C C A D A B E E A B A
# Levels: A B C D E
levels(x) <- 1:5
x
# [1] 1 4 3 1 5 5 1 5 2 3 3 1 4 1 2 5 5 1 2 1
# Levels: 1 2 3 4 5

所以你不需要你的功能。你可以简单地做

levels(training$classe) <- 1:5

我们可以看到新列的str显示更改后的值

str(training$classe)
# Factor w/ 5 levels "1","2","3","4",..: 1 1 1 1 1 1 1 1 1 1 ...

请注意，对于这个简单的情况，as.integer(training$classe)也有效。虽然大部分时间都不会那么容易。

Answer 2

如果您要转换classe的{{1}}列，则无需定义自己的功能。您可以使用training_data_subset向量：

LETTERS

尝试用数值替换数据框中的字符值，错误＆＃34;无效因子水平，NA生成＆＃34;

2 个答案: