搜索整个数据库的PHP脚本

Question

$tableArray = array('tbl_course','tbl_faculty');
  if(!empty($_POST["searchField"]))
    {
        $search=$_POST["searchField"];
        foreach( $tableArray as $tblArry)   
        {
           $out .= $tblArry.";";
            $sql_search = "select * from ".$tblArry." where ";
            $sql_search_fields = Array();
            $sql2 = "SHOW COLUMNS FROM ".$tblArry;
            $rs2 =mysql_query($sql2);
            if(mysql_num_rows($rs2)>0){
                while($r2 = mysql_fetch_array($rs2)){
                    $colum = $r2[0];
                    $sql_search_fields[] = $colum." like('%".$search."%')";
                }
            }
            $sql_search .= implode(" OR ", $sql_search_fields);
            $rs3 = mysql_query($sql_search);

        }
    }

问题是我想显示数据库的结果。该脚本循环遍历2个表的列，并基于该表创建一个SQL语句。

我面临的唯一问题是如何从结果集r3中获取数据？