Question

我正在尝试将输出写入文件。但是当我编写这段代码时，它会多次写入同一行。如何多次停止重复同一行？

Java_location是我的输出。

这是我的代码：

a = []
a << java_location
File.open("/home/weblogic/javafoundmodified.txt", 'w+') do |file|
  a.each { |item| file.puts item }
end

我现在得到的输出是：

1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/jre/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/jre/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/jre/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/bin/java
1.7.0_65/u01/java/jdk1.7.0_65/jre/bin/java
1.7.0_65/u01/java/jdk1.7.0_65/jre/bin/java
1.7.0_65/u01/java/jdk1.7.0_65/jre/bin/java

Answer 1

考虑这一点（javalocation中的示例数组）：

javalocation = %w|
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.5.0/opt/itm/v6.2.2/JRE/lx8266/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/jre/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/jre/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/jre/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/bin/java
1.7.0_72/u01/java/jdk1.7.0_72/bin/java
1.7.0_65/u01/java/jdk1.7.0_65/jre/bin/java
1.7.0_65/u01/java/jdk1.7.0_65/jre/bin/java
1.7.0_65/u01/java/jdk1.7.0_65/jre/bin/java
|

File.open("/home/weblogic/javafoundmodified.txt", 'w+') do |file|
  javalocation.uniq.each { |line| file.puts line }
end

在Ruby中只打印文件中唯一的数组元素

1 个答案: