我正在实施自定义UIMenuController
并试图找出答案。如何合法禁用UIMenuController
中UITextfield
的“复制”和“定义”UIMenuItems? Textfield不可编辑。我尝试使用以下方法禁用“复制”:
-(BOOL)canPerformAction:(SEL)action withSender:(id)sender
{
if (action == @selector(copy:))
{
return NO;
}
return [super canPerformAction:action withSender:sender];
}
- (IBAction)tapTextViewGesture:(id)sender {
UIMenuItem *myItem1 = [[UIMenuItem alloc] initWithTitle:@"myItem1" action:@selector(myItem1Pressed:)];
UIMenuItem *myItem2 = [[UIMenuItem alloc] initWithTitle:@"myItem2" action:@selector(myItem2Pressed:)];
UIMenuItem *myItem3 = [[UIMenuItem alloc] initWithTitle:@"myItem3" action:@selector(myItem3Pressed:)];
// Access the application's shared menu
UIMenuController *menu = [UIMenuController sharedMenuController];
[menu setMenuItems:[NSArray arrayWithObjects:myItem1,myItem2,myItem3, nil]];
CGRect menuRect = CGRectMake(20, 50, 200, 0);
// Show the menu from the cursor's position
[menu setTargetRect:menuRect inView:self.view];
[menu setMenuVisible:YES animated:YES];
}
但菜单仍显示“复制”和“定义”UIMenuItems
。如何禁用它们,只留下我的物品?
答案 0 :(得分:7)
最后通过继承UITextView
(为它创建自定义类)并添加
- (BOOL)canPerformAction:(SEL)action withSender:(id)sender
{
if (action == @selector(copy:))
{
return NO;
}
return NO;
}
我的自定义TextView子类的.m文件内部。
之后"复制"不论是否有[menu update]
;
答案 1 :(得分:4)
在viewController.m中实现此实例方法:
**- (BOOL)canPerformAction:(SEL)action withSender:(id)sender {
if ([_targetTextField isFirstResponder]) {
[[NSOperationQueue mainQueue] addOperationWithBlock:^{
[[UIMenuController sharedMenuController] setMenuVisible:NO animated:NO];
}];
}
return [super canPerformAction:action withSender:sender];
}**
此方法检查目标文本字段是否是第一个响应者。如果是,NSOperationQueue为sharedMenuController操作创建一个单独的线程,将其可见性和动画设置为no,以便它不能用于复制,粘贴等。 return语句调用UIResponder的canPerformAction方法来通知它实现它。
答案 2 :(得分:1)
您可以通过继承UITextField
类并重写其canPerformAction::
方法来创建类。
-(BOOL)canPerformAction:(SEL)action withSender:(id)sender
{
// Returning 'NO' here disables all actions on textfield
return NO;
}
答案 3 :(得分:1)
Swift 4.2。 && Xcode 10 对我有用:
override public func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
// Requested action to prevent:
guard action != #selector(copy(_:)) else { return false } // disabling copy
// Further actions to prevent:
// guard action != #selector(cut(_:)) else { return false } // disabling cut
// guard action.description != "_share:" else { return false } // disabling share
return super.canPerformAction(action, withSender: sender)
}
为了完成这项工作,您必须创建UITextField
/ UITextView
的子类,并确保在super.canPerformAction(_:withSender:)
上调用super!
答案 4 :(得分:0)
设置菜单项后添加此项
[menu update];
我希望这能解决您的疑问。 :)