Question

这就是我现在拥有的。它正在工作，但我想编辑随机函数，以便div（这只是一个模型，会有很多，甚至更多！）将是＆＃34;均匀分布＆＃34;根据浏览器的宽度，如果这是有道理的。在某种程度上，不需要水平滚动条！

I think this is a good example.点击Designer的名称（左上角），您就会明白我的意思。请注意这些文件夹如何始终使用整个窗口，无论它有多小或多大？我想模仿那种行为......我只是不知道如何去做...编辑当前的脚本？一种完全不同的方法？

任何输入都将受到高度赞赏。感谢。

HTML

<div id="box1" class="boxes">
<div id="text1">&nbsp;&nbsp;Lorem Ipsum Dolor Sit Amet&nbsp;&nbsp;</div>
</div>

<div id="box2" class="boxes">
<div id="text2">&nbsp;&nbsp;Lorem Ipsum Dolor Sit Amet&nbsp;&nbsp;</div>
</div>

<div id="box3" class="boxes">
<div id="text3">&nbsp;&nbsp;Lorem Ipsum Dolor Sit Amet&nbsp;&nbsp;</div>
</div>

<div id="box4" class="boxes">
<div id="text4">&nbsp;&nbsp;Lorem Ipsum Dolor Sit Amet&nbsp;&nbsp;</div>
</div>

CSS

.boxes {
    position: absolute;
}

#text1 {
    color: white;
    font-family: "Times", Times New Roman, serif;
    font-size: 16px;
    font-weight: bold;
    line-height: 24px;
    background-color: black;
}

    #text2 {
    color: white;
    font-family: "Times", Times New Roman, serif;
    font-size: 16px;
    font-weight: bold;
    line-height: 24px;
    background-color: blue;
}

#text3 {
    color: white;
    font-family: "Times", Times New Roman, serif;
    font-size: 16px;
    font-weight: bold;
    line-height: 24px;
    background-color: green;
}

#text4 {
    color: white;
    font-family: "Times", Times New Roman, serif;
    font-size: 16px;
    font-weight: bold;
    line-height: 24px;
    background-color: red;
}

的javascript

var boxDims = new Array();

function setRandomPos(elements,x,dx){
  elements.each(function(){
    var conflict = true;
    while (conflict) {
        fixLeft=(Math.floor(Math.random()*x)*10) + dx;
        fixTop = (Math.floor(Math.random()*40)*10) + 180;
        $(this).offset({
            left: fixLeft,
            top: fixTop
        });
        var box = {
            top: parseInt(window.getComputedStyle($(this)[0]).top),
            left: parseInt(window.getComputedStyle($(this)[0]).left),
            width: parseInt(window.getComputedStyle($(this)[0]).width),
            height: parseInt(window.getComputedStyle($(this)[0]).height)
        }
        conflict = false;
        for (var i=0;i<boxDims.length;i++) {
            if (overlap(box,boxDims[i])) {
                conflict = true;
                break;
            } else {
                conflict = false;
            }                   
        }
    }
    boxDims.push(box)

  });
}

function overlap(box1,box2) {
  var x1 = box1.left
  var y1 = box2.top;
  var h1 = box1.height;
  var w1 = box1.width;
  var b1 = y1 + h1;
  var r1 = x1 + w1;
  var x2 = box1.left;
  var y2 = box1.top;
  var h2 = box1.height;
  var w2 = box1.width;
  var b2 = y2 + h2;
  var r2 = x2 + w2;

  var buf = 24;

  if (b1 + buf < y2 || y1 > b2 + buf || r1 + buf < x2 || x1 > r2 + buf) return false;
  return true;
}

setRandomPos($(".boxes"),40,40);

Answer 1

我以为我会分享我想出的调整和进一步的解决方案。当当前窗口内没有足够的空间时，确保父容器被扩展，因此不会发生无限循环。

http://codepen.io/Shikkediel/pen/dPOVJp?editors=011

首先通过指定的数字迭代屏幕的象限，使得随机性稍微减少。

$(window).on('load', function() {

var spread, crest, boxes = [];

var margin = 40;
var itemwidth = 50;
var itemheight = 50;
var pad = 25;
var initial = 8;

setArea($(".boxes"));
placeRandom($(".boxes"));

function setArea(items) {

var range = 0, pitch = 0, total = 0;

items.each(function() {
range = $(this).width()+2*pad;
pitch = $(this).height()+2*pad;
total = total+range*pitch;
});

spread = $(window).width();
var term = $(window).height();
var edge = total/spread;

if (term < 4*edge) crest = 4*edge;
else crest = term;

$('#boxcontainer').css({'width': spread, 'height': crest});
spread = $(window).width();
$('#boxcontainer').width(spread);
}

function placeRandom(elements) {

var iter = 0;
var horizontal = spread/2;
var vertical = crest/2;

elements.each(function() {

var object = $(this), box;
iter++;
setPosition();

function setPosition() {

if (iter <= initial) {

var quadrant = iter%4;
if (quadrant == 0) quadrant = 4;
var spaceX = Math.round(Math.random()*(horizontal-itemwidth-margin));
var spaceY = Math.round(Math.random()*(vertical-itemheight-margin));
var bufferX, bufferY;

if (quadrant == 1) {
bufferX = margin;
bufferY = margin;
}
if (quadrant == 2) {
bufferX = horizontal;
bufferY = margin;
}
if (quadrant == 3) {
bufferX = horizontal;
bufferY = vertical;
}
if (quadrant == 4) {
bufferX = margin;
bufferY = vertical;
}
fixleft = spaceX+bufferX;
fixtop = spaceY+bufferY;
object.css({top: fixtop, left: fixleft});
}
else {
fixleft = Math.round(Math.random()*($(window).width()-itemwidth-2*margin))+margin;
fixtop = Math.round(Math.random()*($(window).height()-itemheight-2*margin))+margin;
object.css({top: fixtop, left: fixleft});
}

box = {
top: fixtop,
left: fixleft,
width: object.width(),
height: object.height()
}

if (iter == 1) boxes.push(box);
else {
for (var i=0; i < boxes.length; i++) {
if (encroachOn(box, boxes[i])) setPosition();
}
}
}
boxes.push(box);
object.show();
});
}

function encroachOn(box1, box2) {

var x1 = box1.left;
var y1 = box1.top;
var h1 = box1.height;
var w1 = box1.width;
var b1 = y1+h1;
var r1 = x1+w1;
var x2 = box2.left;
var y2 = box2.top;
var h2 = box2.height;
var w2 = box2.width;
var b2 = y2+h2;
var r2 = x2+w2;

return (x1 < r2+pad && r1+pad > x2 && y1 < b2+pad && b1+pad > y2);
}
});

还要添加一个用于调整大小的附加功能。

编辑 - 这是在Stackoverflow上找到的后者的一个很好的解决方案：

https://stackoverflow.com/a/5490021/3168107

随机不随便

1 个答案: