Question

我有一个PHP返回的JSON数组，PHP的示例输出：

[
  {
    "uid": "1",
    "username": "mike",
    "time_created": "2014-12-27 15:30:03",
    "time_updated": "2014-12-27 15:30:03",
    "time_expires": "2014-12-27 15:30:03"
  },
  {
    "uid": "2",
    "username": "jason",
    "time_created": "2014-12-27 15:31:41",
    "time_updated": "2014-12-27 15:31:41",
    "time_expires": "2014-12-27 15:31:41"
  },
  {
    "uid": "3",
    "username": "david",
    "time_created": "2014-12-27 18:10:53",
    "time_updated": "2014-12-27 18:10:53",
    "time_expires": "2014-12-27 18:10:53"
  }
]

我尝试了几种方法，我尝试了Iterator，我尝试从JSonObject中获取，但似乎没有任何工作！到目前为止，我有这个示例代码：

QJsonDocument jsonResponse = QJsonDocument::fromJson(JData.toUtf8());
QJsonObject jsonObject = jsonResponse.object();
for (QJsonObject:: Iterator it = jsonObject.begin(); it != jsonObject.end(); ++it) {
QJsonArray array= (*it).toArray();
foreach (const QJsonValue & v, array)
qDebug() << v.toString();

我尝试了其他几种方法，没有运气。我需要遍历这个JSON数据。请指教。我使用的是QT 5.4，C ++。

Answer 1

首先通过将数据放到QString来验证您的代码（并不意味着它需要完成，仅用于我的调试）。发现了几个问题：

数组位于文档的上一层。
QJsonValue :: toString（）无法遍历嵌套结构但是QJsonValue （变量v）仍然可以通过qDebug（）流打印。

QString JsonStr =
"["
  "{"
    "\"uid\": \"1\","
    "\"username\": \"mike\","
    "\"time_created\": \"2014-12-27 15:30:03\","
    "\"time_updated\": \"2014-12-27 15:30:03\","
    "\"time_expires\": \"2014-12-27 15:30:03\""
  "},"
  "{"
    "\"uid\": \"2\","
    "\"username\": \"jason\","
    "\"time_created\": \"2014-12-27 15:31:41\","
    "\"time_updated\": \"2014-12-27 15:31:41\","
    "\"time_expires\": \"2014-12-27 15:31:41\""
  "},"
  "{"
    "\"uid\": \"3\","
    "\"username\": \"david\","
    "\"time_created\": \"2014-12-27 18:10:53\","
    "\"time_updated\": \"2014-12-27 18:10:53\","
    "\"time_expires\": \"2014-12-27 18:10:53\""
  "}"
"]";

QJsonDocument jsonResponse = QJsonDocument::fromJson(JsonStr.toUtf8());
QJsonArray array = jsonResponse.array();
// print
foreach (const QJsonValue & v, array)
{
    qDebug() << v;
}

// or parse
foreach (const QJsonValue& v, array)
{
    QJsonObject o = v.toObject();
    qDebug() << o["username"];
    qDebug() << o["time_expires"];
}

PHP解析JSON数组输出

1 个答案: