作为另一个函数错误的参数 - c ++

时间:2015-01-02 01:07:44

标签: c++

我有以下功能:

CompareType CompareByCitizensNum(const City& c1, const City& c2) {
        if (c1.getNumCitizens() > c2.getNumCitizens()
                || ((c1.getNumCitizens() == c2.getNumCitizens())
                        && (c1.getCityId() > c2.getCityId()))) {
            return BIGGER;
        } else if (c1.getCityId() == c2.getCityId()) {
            return EQUALS;
        }
        return SMALLER;
    }

这是需要使用此功能的方法:

avlTreeVertix(City newKey, avlTreeVertix* fatherToBe,
            CompareType (*compare)(const City&, const City&)) :
            bf(0), key(newKey), RightHigh(0), LeftHigh(0), vertexesInSubTree(1), father(
                    fatherToBe), childL(NULL), childR(
            NULL), compare(compare) {
        CHECK_NULL(father,);
        if (compare(key, father->key) == BIGGER) {
            //if (isGreater(father)) {
            father->childR = this;
        } else {
            father->childL = this;
        }
    }

我尝试通过以下行调用它:

rankTree = new avlTreeVertix(c, NULL, CompareByCitizensNumx);

但它说:

  

没有用于调用wet2::avlTreeVertix::avlTreeVertix(wet2::City&, NULL, <unresolved overloaded function type>)

的匹配函数

有什么想法吗? 谢谢!

1 个答案:

答案 0 :(得分:0)

好的家伙,问题是该函数是一个成员函数,所以我需要在函数decleration处添加一个“静态”,现在它正在工作!愚弄我...