我尝试使用asp.net和c#按顺序(1到...)对列进行排序。在做了一些研究后,似乎我需要将SQL Server中的列类型更改为int但是这不可能,因为列存储门牌号码,我最终可能会有一个门牌号码10a(例如)所以当前设置到varchar。因此,它没有正确排序列。我已经尝试将相关列作为int进行转换,但是当运行应用程序时,我在gridview中遇到了它的绑定错误,我还尝试了其他这个作为* 1但在运行时仍然在绑定部分上出错
SQL语句
SELECT DISTINCT tblcontact.ContactID, tblcontact.Forename, tblcontact.Surname,
tbladdress.[House Number], tbladdress.AddressLine1, tbladdress.AddressLine2,
tblcontact.[Business Name] FROM tblcontact INNER JOIN tbladdress ON tblcontact.AddressID = tbladdress.AddressID
LEFT OUTER JOIN tblDonate
ON tblcontact.ContactID = tblDonate.ContactID
WHERE (tbladdress.CollectionArea = @CollectionArea) AND
(tbladdress.AddressLine1 = @drpCollectionStreet)
ORDER BY tbladdress.[House Number] ASC
Gridview标记
<asp:TemplateField HeaderText="House Number">
<EditItemTemplate>
<asp:TextBox ID="txtHouseNum" runat="server" Text='<%# Bind("[House Number]") %>'></asp:TextBox>
</EditItemTemplate>
<ItemTemplate>
<asp:Label ID="lblHouseNum" runat="server" Text='<%# Bind("[House Number]") %>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
以下是其排序方式的示例
21
22
27
28
5
6
8
9
这是我如何转换为int,它在SQL中排序很好,但我在Bind上得到错误(上图)
SELECT DISTINCT tblcontact.ContactID, tblcontact.Forename, tblcontact.Surname, cast(tbladdress.[House Number] as int),
tbladdress.AddressLine1, tbladdress.AddressLine2, tblcontact.[Business Name]
FROM tblcontact INNER JOIN tbladdress ON tblcontact.AddressID = tbladdress.AddressID
LEFT OUTER JOIN tblDonate ON tblcontact.ContactID = tblDonate.ContactID
WHERE (tbladdress.CollectionArea = 'Queens Park') AND (tbladdress.AddressLine1 = 'Kings Road')
ORDER BY cast(tbladdress.[House Number] as int)
运行时错误
这是运行时的错误(这是最有意义的)
"House Number is neither a DataColumn nor a DataRelation for table DefaultView."}
答案 0 :(得分:1)
要以数字方式对街道号码进行排序,您需要将它们作为数字投射。当然,麻烦的是诸如“10a”之类的字符串不能被转换为INT。答案是从[House Number]列中提取数字字符,然后进行演员表。以下是对ORDER BY子句执行此操作:
...
ORDER BY CAST(SUBSTRING(tbladdress.[House Number], PATINDEX('%[0-9]%', tbladdress.[House Number]),
1 + PATINDEX('%[0-9][^0-9]%', tbladdress.[House Number] + ' ') -
PATINDEX('%[0-9]%',tbladdress.[House Number])) AS INT)
请参阅http://blogs.lessthandot.com/index.php/DataMgmt/DataDesign/extracting-numbers-with-sql-server/,了解复杂外观公式的工作原理。
答案 1 :(得分:1)
从选择cast
中删除column list
。只保留在order by
,它会按顺序排列结果。
select A.ContactID,
A.Forename,
A.Surname,
A.[House Number],
A.AddressLine1,
A.AddressLine2,
A.[Business Name] from (
SELECT DISTINCT tblcontact.ContactID,
tblcontact.Forename,
tblcontact.Surname,
tbladdress.[House Number],
tbladdress.AddressLine1,
tbladdress.AddressLine2,
tblcontact.[Business Name]
FROM tblcontact
INNER JOIN tbladdress
ON tblcontact.AddressID = tbladdress.AddressID
LEFT OUTER JOIN tblDonate
ON tblcontact.ContactID = tblDonate.ContactID
WHERE ( tbladdress.CollectionArea = 'Queens Park' )
AND ( tbladdress.AddressLine1 = 'Kings Road' )) A
ORDER BY Cast(tbladdress.[House Number] AS INT)
答案 2 :(得分:0)
正确答案是JohnS和NoDisplayName答案的组合,这要归功于你们两个
select A.ContactID,
A.Forename,
A.Surname,
A.[House Number],
A.AddressLine1,
A.AddressLine2,
A.[Business Name] from (
SELECT DISTINCT tblcontact.ContactID,
tblcontact.Forename,
tblcontact.Surname,
tbladdress.[House Number],
tbladdress.AddressLine1,
tbladdress.AddressLine2,
tblcontact.[Business Name]
FROM tblcontact
INNER JOIN tbladdress
ON tblcontact.AddressID = tbladdress.AddressID
LEFT OUTER JOIN tblDonate
ON tblcontact.ContactID = tblDonate.ContactID
WHERE ( tbladdress.CollectionArea = 'Queens Park' )
AND ( tbladdress.AddressLine1 = 'Kings Road' )) A
ORDER BY CAST(SUBSTRING(A.[House Number], PATINDEX('%[0-9]%', A.[House Number]),
1 + PATINDEX('%[0-9][^0-9]%', A.[House Number] + ' ') -
PATINDEX('%[0-9]%',A.[House Number])) AS INT)