我试图为谷歌搜索API制作一个简单的球衣休息客户端。
Client client = ClientBuilder.newClient();
WebTarget target = client.target("https://www.googleapis.com/customsearch/v1");
target.queryParam("q", "mobile");
Response response = target.request().get();
System.out.println(response.readEntity(String.class));
正如您已经注意到我没有包含key
和cx
。不用担心,这只是一个简单的演示。
访问网址https://www.googleapis.com/customsearch/v1?q=mobile
时,回复是
{
"error": {
"errors": [
{
"domain": "usageLimits",
"reason": "dailyLimitExceededUnreg",
"message": "Daily Limit for Unauthenticated Use Exceeded. Continued use requires signup.",
"extendedHelp": "https://code.google.com/apis/console"
}
],
"code": 403,
"message": "Daily Limit for Unauthenticated Use Exceeded. Continued use requires signup."
}
}
这是正确的,因为我还没有包含key
和cx
。当我执行上面的代码时,我得到的响应是
{
"error": {
"errors": [
{
"domain": "global",
"reason": "required",
"message": "Required parameter: q",
"locationType": "parameter",
"location": "q"
}
],
"code": 400,
"message": "Required parameter: q"
}
}
相当于访问没有任何参数的网址(https://www.googleapis.com/customsearch/v1
),尽管我已添加此target.queryParam("q", "mobile");
。我做错了吗?
上面的代码属于一个mavenized项目,依赖是
<dependency>
<groupId>org.glassfish.jersey.core</groupId>
<artifactId>jersey-client</artifactId>
<version>2.14</version>
</dependency>
答案 0 :(得分:27)
链接电话
Response response= client.target("https://www.googleapis.com/customsearch/v1")
.queryParam("q", "mobile").request().get();
来自文档:
返回:新的目标实例。
注意: - 如果没有链接,则获取新创建的 webtarget 实例并使用它。
WebTarget webTarget = client.target(snapshotGeneratorUrl);
webTarget = webTarget.queryParam("foo","foo").queryParam("bar",bar);
Response response = webTarget.request().get();
答案 1 :(得分:1)
您可以使用UriBuilder,并将uriBuilder实例作为client.target提供