在opencv中执行dct时出​​错

时间:2015-01-01 11:51:17

标签: c++ opencv dct

当我尝试在opencv中实现dct时,为什么会出现以下错误?

Assertion failed (type == CV_32FC1 || type == CV_64FC1) in dct,

这是代码:

#include <cv.h>
#include "opencv2/imgproc/imgproc.hpp"
#include <highgui.h>
#include <iostream>

using namespace cv;
using namespace std;

int main()
{
    Mat image,dimage(image);
       image = imread( "lena.jpg", 1 );

      if( !image.data )
        {
          printf( "No image data \n" );
           return -1;
         }

        namedWindow( "Display Image", CV_WINDOW_AUTOSIZE );
        imshow( "Display Image", image );
        dimage=Mat::zeros(image.rows,image.cols,CV_32F);
        dct(image, dimage, DCT_INVERSE == 0 );

        namedWindow( "DCT Image", CV_WINDOW_AUTOSIZE );
        imshow( "DCT image", dimage );
        waitKey(0);

       return 0;
}

1 个答案:

答案 0 :(得分:2)

你必须先将你的图像从uchar转换为float(然后再回到uchar):

// also please use the c++ headers, not the old c-ones !

#include "opencv2/core/core.hpp" 
#include "opencv2/imgproc/imgproc.hpp"
#include "opencv2/highgui/highgui.hpp"

Mat image = imread( "lena.jpg", 0 ); // grayscale

Mat fimage;
image.convertTo(fimage, CV_32F, 1.0/255); // also scale to [0..1] range (not mandatory)

// you're lucky with lena (512x512), for odd sizes, you have to 
// pad it to pow2 size, or use dft() instead:
Mat dimage;
dct( fimage, dimage ); 
// process dimage,
// then same way back:
dct( dimage, dimage, DCT_INVERSE );
dimage.convertTo(image, CV_8U); // maybe scale back to [0..255] range (depending on your processing)

imshow("result",image);
waitKey();