Question

我想知道如何编写一个方法来计算每个单词字母的单词数和数量例如，如果输入是“蓝天”，作为回报，我采取的东西，告诉我有3个字3个字母4个字母3个字母

我发现这段代码已经

了

public static int countWords(String s){

    int wordCount = 0;

    boolean word = false;
    int endOfLine = s.length() - 1;

    for (int i = 0; i < s.length(); i++) {
        // if the char is a letter, word = true.
        if (Character.isLetter(s.charAt(i)) && i != endOfLine) {
            word = true;
            // if char isn't a letter and there have been letters before,
            // counter goes up.
        } else if (!Character.isLetter(s.charAt(i)) && word) {
            wordCount++;
            word = false;
            // last word of String; if it doesn't end with a non letter, it
            // wouldn't count without this.
        } else if (Character.isLetter(s.charAt(i)) && i == endOfLine) {
            wordCount++;
        }
    }
    return wordCount;
}

我非常感谢能得到的任何帮助！谢谢！

Answer 1

第1步 - 使用空格分隔符查找句子中的单词数。

 String CurrentString = "How Are You";
    String[] separated = CurrentString.split(" ");
    String sResultString="";
    int iWordCount = separated.length;
    sResultString = iWordCount +" words";

第2步 - 在每个单词中查找字母数。

    for(int i=0;i<separated.length;i++)
    {
    String s = separated[i];
    sResultString = sResultString + s.length + " letters ";
    }

// Print sResultString

Answer 2

看看http://www.tutorialspoint.com/java/java_string_split.htm。您应该能够使用Java String.split（）函数以空格“”分隔字符串。这应该给你一个包含每个单词的数组。然后它只是找到每个单词的长度。

Answer 3

计算可能有帮助的词语

  public static int countWords(String str)
        {
            int count = 1;
            for (int i=0;i<=str.length()-1;i++)
            {
                if (str.charAt(i) == ' ' && str.charAt(i+1)!=' ')
                {
                    count++;
                }
            }
            return count;
        }
        public static void main(String[] args)
        {
            Scanner in = new Scanner(System.in);
            System.out.print("Enter a sentence: ");
            String sentence = in.nextline();
            System.out.print("Your sentence has " + countWords(sentence) + " words.");
        }

Answer 4

这是我的代码 -

   public void countWordsLetters(String s){
        String str[]=s.split(" ");
        System.out.println("No. of words in string::"+str.length);
        for (int i=0;i<str.length;i++){
            System.out.println("No of letters in "+i+" word "+str[i].length());
        }
    }

Answer 5

Buddy，上面的大部分答案都是正确的，但是在计算String中的字符时没有人考虑过空格。希望你也能包含它。

          for(int j=0;j<name.length();j++){ //here is name is my string

          if(Character.isWhitespace(name.charAt(j))){

            }else{
                count+=1;
            }

      }
      System.out.println("The word count is "+count);

Answer 6

这是我的回答，这要感谢Sahil Nagpal的启发：

package exercise;

导入java.util.Scanner;

公共类method_letter {

public static void main(String[] args) {
    Scanner in = new Scanner(System.in);
    System.out.println("enter any string");
    String s=in.nextLine();
    System.out.println("the letter count :"+lettercount(s));

}
public static int lettercount (String s) {
    int count=0;
    for (int i=0; i<s.length(); i++) {
        if(Character.isWhitespace(s.charAt(i))){

        }else {
            count+=1;
        }
    }
    return count;
}

}

如何计算每个单词的字母

6 个答案: