Question

如何添加多个php命令，如：

$email = $_POST['email'];

//get the user.id 
$result = mysql_query("SELECT user.id FROM user WHERE user.email LIKE '$email'");
$user_id = mysql_fetch_array($result);
$user_id = $user_id["id"];

//fill the album -> "Profilbilder"

mysql_query("INSERT INTO `album` (`user_id`, `name`) VALUES ('$user_id', 'Profilbilder')") or    die(mysql_error()); 

//get the album.id
$result = mysql_query("SELECT album.id FROM album WHERE album.user_id = '$user_id'");
$album_id = mysql_fetch_array($result);
$album_id = $album_id["id"];        


mysql_query("INSERT INTO `foto` (`album_id`, `name`, `zeitstempel`, `link`) VALUES ('$album_id',    '$file_name', NOW(), '$file_path')") or die(mysql_error());

..在一个大命令中获取数据库信息？

Answer 1

您实际上可以将查询结果插入表中，如下所示：

$query="INSERT INTO `album` 
           (`user_id`, `name`) 
           SELECT user.id, 'Profilbilder' 
           FROM `user` 
           WHERE user.email LIKE '%$email%'";

如何将多个PHP命令合二为一？

1 个答案: