我花了几天时间试图找出凌空和凌空终于设法找到使用Method.POST的方法。我使用StringRequest将email_address参数传递给我的PHP。现在它返回一个JSON字符串:
{"user_id":1,"email_address":"adminuser"}
但是,我无法使用普通的getString()方法提取数据。它给了我"没有价值"错误。这是我的代码。只是它的摘录:
// Login button
btnLogin = (Button) findViewById(R.id.btnLogin);
// Login button click event
btnLogin.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String param = txtUsername.getText().toString();
postData(param);
}
});
}
/**
* Posting parameter
* */
private void postData(final String param) {
// Get username, password from EditText
String username = txtUsername.getText().toString();
String password = txtPassword.getText().toString();
// Check if username, password is filled
if(username.trim().length() > 0 && password.trim().length() > 0){
if(username.equals("adminuser") && password.equals("test")){
RequestQueue rq = Volley.newRequestQueue(this);
StringRequest postReq = new StringRequest(Request.Method.POST, url, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.d(TAG, response.toString());
try {
JSONObject person = new JSONObject();
String name = person.getString("user_id");
String email = person.getString("email_address");
//Store session
session.createLoginSession(name, email);
// Staring MainActivity
Intent intent = new Intent(getApplicationContext(), MainActivity.class);
startActivity(intent);
finish();
//}
} catch (JSONException e) {
e.printStackTrace();
Toast.makeText(getApplicationContext(), "Error: " + e.getMessage(), Toast.LENGTH_LONG).show();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.d(TAG, "Error: " + error.getMessage());
Toast.makeText(getApplicationContext(), error.getMessage(), Toast.LENGTH_LONG).show();
}
}) {
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String, String> params = new HashMap<String, String>();
params.put("email_address", param);
return params;
}
};
rq.add(postReq);
}
}
}
我有一种感觉,因为响应以字符串形式返回(我可能是错的)。但是我尝试过使用自定义请求,gson但是无论我使用post方法做什么都行不通。 StringRequest是实际返回的唯一方法,但现在,我无法从中提取数据。我想将数据存储在会话中。
如果有人可以提供帮助,那就太棒了,因为我用Google搜索了&amp;尝试了我能找到的任何解决方案,但无济于事。谢谢!
答案 0 :(得分:11)
@Override
public void onResponse(String response) {
Log.d(TAG, response.toString());
try {
//Do it with this it will work
JSONObject person = new JSONObject(response);
String name = person.getString("user_id");
String email = person.getString("email_address");
//Store session
session.createLoginSession(name, email);
// Staring MainActivity
Intent intent = new Intent(getApplicationContext(), MainActivity.class);
startActivity(intent);
finish();
//}
} catch (JSONException e) {
e.printStackTrace();
Toast.makeText(getApplicationContext(), "Error: " + e.getMessage(), Toast.LENGTH_LONG).show();
}
}